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3 years ago

11

Find the value of x,y, and z and please show all your work.

1 answer:

yanalaym [24]3 years ago

4 0

Answer:

Because the three sides of the triangle are equal then the three angles will be 60ْ

3x = 60 .... x=20

4y=60 ....y=15

5z =60 ..... z=12

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HELP FAST PLEASE!!!!!!

Elodia [21]

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3 years ago

Raquel takes her pulse in order to determine her resting heart rate, measured in beats per minute (\text{bpm})(bpm)left parenthe

murzikaleks [220]

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Raquel's heart rate is slower.

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4 years ago

The polynomial x^2+3x-1 is a factor of x^4+3x^3-2x^2-3x+1 true or false?

pashok25 [27]

Answer:

Yes, it is true that $x^2+3x-1$ is a factor of $x^4+3x^3-2x^2-3x+1$ .

Step-by-step explanation:

Let us try to factorize $x^4+3x^3-2x^2-3x+1$

$x^4+3x^3-2x^2-3x+1\\\Rightarrow x^4-2x^2+1-3x+3x^3$

Let us try to make a whole square of the given terms:

$\Rightarrow (x^2)^2-2\times x^2 \times 1+1^2+3x^3-3x\\\Rightarrow (x^2-1)^2+3x^3-3x\\$

--------------

Formula used above:

$a^{2} -2 \times a \times b +b^{2} = (a-b)^2$

In the above equation, we had $a = x, b = 1$ .

--------------

Further solving the above equation, taking $3x$ common out of $3x^3-3x$

$\Rightarrow (x^2-1)^2+3x(x^2-1)\\$

Taking $(x^{2} -1)$ common out of the above term:

$\Rightarrow (x^2-1)((x^2-1)+3x)\\\Rightarrow (x^2-1)(x^2+3x-1)$

So, the two factors are $(x^2-1)\ and\ (x^2+3x-1)$ .

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7 0

3 years ago

Monique purchases a $5,100 dining room set. She can't afford to pay cash, so she uses the installment plan, which requires an 18

just olya [345]

Answer:

$918 is her down payment

Step-by-step explanation:

.18×5100

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3 years ago

Triangle ABC is labeled with points A(5, 2), B(1, 2) and C(3, 6) on a coordinate plane. Find the coordinates of A' B' C' after a

Ilia_Sergeevich [38]

Answer:

After reflection over the x-axis, we have the coordinates as follows;

A’ (5,-2)

B’ ( 1,-2)

C’ (3,-6)

Step-by-step explanation:

Here, we want to find the coordinates A’ B’ and C’ after a reflection over the x-axis

By reflecting over the x-axis, the y-coordinate is bound to change in sign

So if we have a Point (x,y) and we reflect over the x-axis, the image of the point after reflection would turn to (x,-y)

We simply go on to negate the value of the y-coordinate

Mathematically if we apply these to the given points, what we get are the following;

A’ (5,-2)

B’ ( 1,-2)

C’ (3,-6)

4 0

3 years ago