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Oksi-84 [34.3K]
3 years ago
8

Esmeralda bought " p" pounds of peanuts at $3 per pound and " a" pounds of almonds at $6 per pound . write an algebraic expressi

on for the cost of Esmeralda's purchase.
Mathematics
1 answer:
Andru [333]3 years ago
8 0
 answer would be 3p+6a
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Jan and Wayne went to the store to buy some groceries. Jan bought 2 cans of corn beef hash and 3 cans of creamed chipped beef fo
marin [14]
You can solve this by using the system of equations.
Jan - 4.95 = 2H + 3C
Wayne - 5.45 = 3H + 2C

Use elimination.
-3(2H + 3C = 4.95)
2(3H + 2C = 5.45)

Solve. And you'll get:
-6H + (-9C) = -14.85
6H + 4C = 10.9

Cross out -6H and 6H because they cancel out. And you're left with:
-9C = -14.85
4C = 10.9

Add -9C with 4C, and -14.85 with 10.9.
-5C = -3.95

Divide each side with -5.
C = $0.79

Now to figure out what H is, just substitute the C in one of the equations with 0.79.
5.45 = 3H + 2(0.79)
5.45 = 3H + 1.58
-1.58            -1.58
3.87 = 3H
3.87/3 = 3/3(H)
1.29 = H

Finished!
7 0
4 years ago
Read 2 more answers
Which type of function is shown in the table<br> below?
Inessa [10]

Answer:

Not a function

Step-by-step explanation:

Since 2 different points have the same x-coordinte, the relation is not a function.

8 0
2 years ago
Let the random variable Q represent the number of students who go to a certain teacher's office hour each day. The standard devi
postnew [5]

Answer: А. On average, the number of students going to an office hour varies from the mean by about 2.2 students

Step-by-step explanation:

The standard deviation is a measure of spread, which gives how values deviate from the average or mean value of a particular distribution. Hence, the standard deviation is usually defined about the average value of a distribution.

Therefore, for a certain random variable representing the number of student who visits office hours, the standard deviation will be defined about the average or mean value of the random variable Q.

Thus, stated as ; number of students going to an office hour varies from the mean by 2.2 on average.

4 0
2 years ago
Read 2 more answers
A mobile company charges a fixed rate of x cents per minute for the first 120 minutes of talk time and another rate of y cents p
patriot [66]

Answer:

$21.2

Step-by-step explanation:

From the problem given, we express them as algebra so that we can easily solve;

    the total charge on a call greater than 120min is given as;

   120x + y(n - 120) = total cost of call

where n is the number of minutes which is greater than 120;

  •   Ethan paid $26.80  for 175 mins

  n = 175min here;

      120x + y(175 - 120) = 26.80

       120x + 55y = 26.80 ----- (I)

  • $32.40 for 210 minutes

      n = 210min

       120x + y(210 - 120) = 32.4

       120x + 90y = 32.4 ----- (II)

Now let us solve both equations for y and x;

      120x + 55y = 26.80 ----- (I)

     120x + 90y = 32.4 ----- (II)

subtract the two equations;

             90y - 55y = 32.4 - 26.8

                  35y = 5.6

                       y = \frac{5.6}{35}  = 0.16cents

then x;

       120x = 26.8 - 55y from equation I

       120x = 26.8 - 55(0.16)

       120x = 18

            x = \frac{18}{120}  = 0.15cents

Find the cost of 140min of talk time;

  n =140min;

      =  120(0.15) + 0.16(140 - 120)

      = 18 + 0.16(20)

      = 18 + 3.2

      = $21.2

4 0
3 years ago
What is the common difference in this sequence: 4, 13, 22, 31, 40?
IgorC [24]

Answer:

9

Step-by-step explanation:

To find the common difference, take the second term and subtract the first term

13-4 =9

Lets check:

Take the third term and subtract the second term

22-13 =9

The common difference is 9

5 0
3 years ago
Read 2 more answers
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