For the given situation we have a total of 259,459,200 permutations.
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How many permutations are?</h3>
First, how we know that it is a permutation?
Because the order matters, we aren't only selecting 8 out of the 15 people, but these 8 selected also have an order (is not the same thing to finish the race first than fourth, for example).
Then we need to find the number of permutations, to do it, we need to find the numbers of options for each of the 8 positions.
- For the first position there are 15 options.
- For the second position ther are 14 options (one runner already finished).
- For the third position there are 13 options.
- And so on.
Then the total number of permutations (product between the numbers of options) is:
P = 15*14*13*12*11*10*9*8 = 259,459,200
If you want to learn more about permutations:
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Answer:
240 ft^2
Step-by-step explanation:
area: (24+16)12/2=240 ft^2
(the area of a trapezoid is the sum of the bases multiplied by the height over 2.)
Answer:
x³-2x²-4x+8
Step-by-step explanation:
a1=x+2
a2=x²-4⇒q=a2/a1=x-2
⇒a3=q.a2=(x-2).(x²-4)=x³-2x²-4x+8
9514 1404 393
Answer:
(c) (3, 6)
Step-by-step explanation:
The only point that is on the line is (3, 6).
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I find a graphing calculator to be a useful tool.
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For solving this "by hand," you put the x- and y-values into the equation and check to see if it is true.
A. 2(0) +3(12) = 36 ≠ 24
B. 2(2) +3(9) = 31 ≠ 24
C. 2(3) +3(6) = 24 . . . . . a solution
D. 2(8) +3(0) = 16 ≠ 24
Answer:
John has $21.
Step-by-step explanation:
Let John's "wealth" be w. Then 2w+8 = 50, or 2w = 42, or w = 21.
John has $21. Eight more than twice this is 42+8 = 50, as expected.
