Question

PLZ HURRY IT'S URGENT!!!

Answer 1

Answer:

B) $\frac{2}{6}\times \frac{1}{5}$

Step-by-step explanation:

Number of blue marbles =$N(blue)=4$

Number of green marbles=$N(green)=2$

Total number of balls=$N=N(blue)+N(green)=4+2=6$

Probability of drawing a green marble on first draw= $P(green_1)=\frac{N(green)}{N}=\frac{2}{6}$

After drawing a green marble a 2nd draw is made without replacement.

So, now $N(green)=2-1=1$ and $N=6-1=5$

Probability of drawing a green marble on 2nd draw=$\frac{N(green)}{N}=P(green_2)=\frac{1}{5}$

∴ Probability of drawing a green marble on both your first and second draws=$P(green_1)\times P(green_2)=\frac{2}{6}\times \frac{1}{5}$