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kupik [55]
3 years ago
14

PLZ HURRY IT'S URGENT!!!

Mathematics
1 answer:
natulia [17]3 years ago
4 0

Answer:

B) \frac{2}{6}\times \frac{1}{5}

Step-by-step explanation:

Number of blue marbles =N(blue)=4

Number of green marbles=N(green)=2

Total number of balls=N=N(blue)+N(green)=4+2=6

Probability of drawing a green marble on first draw= P(green_1)=\frac{N(green)}{N}=\frac{2}{6}

After drawing a green marble a 2nd draw is made without replacement.

So, now N(green)=2-1=1 and N=6-1=5

Probability of drawing a green marble on 2nd draw=\frac{N(green)}{N}=P(green_2)=\frac{1}{5}

∴ Probability of drawing a green marble on both your first and second draws=P(green_1)\times P(green_2)=\frac{2}{6}\times \frac{1}{5}

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