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Rom4ik [11]
3 years ago
12

What is the order of rotational symmetry of a kite? A) 0 B) 1 C) 2 D) 4

Mathematics
2 answers:
Mashutka [201]3 years ago
5 0

Answer:

it would be , b 1

Step-by-step explanation:

Phoenix [80]3 years ago
4 0

Answer:

b

Step-by-step explanation:

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URGENT URGENT URGENT!!!<br> HELP PLEASE!!
viva [34]

Answer:

Step-by-step explanation:

I think it’s b correct me if I’m wrong

3 0
3 years ago
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Solve for x. x + 7 -3 = 1<br><br><br> i need help
MA_775_DIABLO [31]
X+7-3=1 X+4=1 -4 -4 X=-3 Copy exactly how you see it
8 0
3 years ago
Simplify<br> Enter answer in box:
lesantik [10]

(3/5 + -1/4)/(7/10)

get a common denominator of 20

3/5 * 4/4 =12/20

-1/4 * 5/5 = -5/20

7/10 *2/2 = 17/20

replace

(12/20 - 5/20)/(14/20)

add the top

(7/20)/(14/20)

copy dot flip

7/20 * 20/14

7/14

1/2


7 0
3 years ago
Read 2 more answers
Find all solutions to the equation.<br><br> cos2x + 2 cos x + 1 = 0
yanalaym [24]
For cos(2x) * (2cos(x) + 1) = 0, use the double angle identity for cos(2x), which is cos^2 x - sin^2 x = cos^2 x - (1-cos^2) = 2cos^2 x - 1.
So we have (2cos^2 x - 1)(2cos x + 1) = 0. So 2cos^2 x -1 = 0 or x = 0 and 2pi.
For 2sec^2 x + tan^2 x - 3 = 0, use the identity sec^2 x = tan^2 x + 1, so we have
2(tan^2 x + 1) + tan^2 x - 3 = 0 or
<span>2tan^2 x + tan^2 x - 1 = 0 or
</span>3 tan^2 x = 1.

So x = pi/2, pi/2 + pi = 3pi/2.

5 0
3 years ago
To assess the accuracy of a laboratory scale, a standard weight that is known to weigh 1 gram is repeatedly weighed 4 times. The
zhannawk [14.2K]

Answer:

(0.9464,1.034)

Step-by-step explanation:

First find the mean μ  of all values as;

(0.95+1.02+ 1.01+ 0.98 ) /4 =0.99

μ=0.99

Find the standard deviation as;

-For each value subtract the mean and square the results

0.95-0.99 = -0.04 , -0.04² = 0.0016

1.02-0.99= 0.03, 0.03²=0.0009

1.01-0.99= 0.02, 0.02²= 0.0004

0.98-0.99 = -0.01, -0.01²=0.0001

Find mean of squared deviations as;

(0.0016+0.0009+0.0004+0.0001)/4 =0.00075 ----variance

Standard deviation = √0.00075 = 0.0274

δ = 0.0274

n=4

Thus n< 30 , confidence interval for μ = x ± t*δ/√n ---------(i)

Degree of freedom (df) = n-1 =4-1 =3

The t value for 95% confidence with df= 3 is t=3.182

Substituting the values in equation (i)

0.99 ± 3.182 * 0.0274/√4

0.99 ± 3.182 * 0.0274/2

0.99 ± 3.182 * 0.0137

0.99 ± 0.0436

(0.9464,1.034)

8 0
3 years ago
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