Given:
surveyed 3/4 of the population
2/3 of the surveyed students are into school clubs or sports team.
Multiply the fractions:
1) Multiply numerators
2) Multiply denominators
3) Simplify fraction
3/4 * 2/3 = 3*2 / 4*3 = 6/12
6/12 can be simplified into 1/2
4a) 3 rows and 4 columns
4b) 2 of the rows gray
4c) 4 of the gray squares black
4d) 1/2 of the students participate in school clubs or sports team
Answers and Step-by-step explanation:
Hypotheses are:
H o=19.8
H 1 ≠19.8
Here we have following information:
s=2.45, X bar=20.1, n=50
So test statistics will be
t=20.1-19.8/(2.45/
=0.87
Degree of freedom : d f = n - 1 = 50 - 1 =49
Test is two tailed so critical value of the test is -1.30 and 1.30.
Rejection region:
if t < -1.30 and t > 1.30, reject H o
Since test statistics lie in the rejection region so we fail to reject the null hypothesis.
(b)
The observed significance of the test is
P value =0.3885
(c)
Since p value is greater than 0.20 so we fail to reject the null hypothesis.
X+ y <span>≥ </span>12
2.75x +3.50y < 35
Hope this helps
<span>A. The angles are neither complementary nor supplementary.
As their sum is neither equal to 90 nor 180, they are none of them
Hope this helps!</span>