Given:
The graph of triangle PQR and triangle P'Q'R'.
To find:
The transformation that will map the triangle PQR onto P'Q'R'.
Solution:
From the given graph it is clear that the triangle PQR is formed in II quadrant and its base lies on the negative direction of x-axis.
The triangle P'Q'R' is formed in IV quadrant and its base lies on the positive direction of x-axis.
This is possible it the figure is rotated 180 degrees about the origin.
Therefore, the correct option is A.
Answer:
26%
Step-by-step explanation:
Given that Dan has 59 new email messages and 13 have attachment then the proportion that have attachments may be expressed as a ratio of the number with attachments to the total number of emails.
Hence proportion of the email messages have attachments as a percentage
= 13/50 * 100%
= 26%
This means that 26% of the emails received have attachments
So than i understand it right and this 4 turning points mean 4 corners so from this result that this polynomial has minimum 360 degrees
hope this will help you
Answer:
B
Step-by-step explanation:
Using the determinant to determine the type of zeros
Given
f(x) = ax² + bx + c ( a ≠ 0 ) ← in standard form, then the discriminant is
Δ = b² - 4ac
• If b² - 4ac > 0 then 2 real and distinct zeros
• If b² - 4ac = 0 then 2 real and equal zeros
• If b² - 4ac < 0 then 2 complex zeros
Given
f(x) = (x - 1)² + 1 ← expand factor and simplify
= x² - 2x + 1 + 1
= x² - 2x + 2 ← in standard form
with a = 1, b = - 2, c = 2, then
b² - 4ac = (- 2)² - (4 × 1 × 2) = 4 - 8 = - 4
Since b² - 4ac < 0 then the zeros are complex
Thus P(x) has no real zeros
