Well, a distance-preserving transformation is called a rigid motion, and the name suggests that it <em>moves the points of the plane around in a rigid fashion.</em>
A transformation is distance-preserving if the distance between the images of any two points and the distance between the two original points are equal.
If that's confusing, I get it; basically if you transform something, the points from the transformation are image points. Take the distance from a pair of image points, and take the distance from a pair of original points, and they should be the same for a <em>rigid </em>motion.
I keep emphasizing this b/c not all transformations preserve distance; a dilation can grow or shrink things. But if you didn't go over dilations, don't say nothin XD
Answer:
The total area is 66
Step-by-step explanation:
That would be 25 units. You can draw it out and you would get 25 units, or you could see the difference in -10 and 15, their distance would be 25 units.
That made no sense.
Answer:
3x - 4y = -4
Step-by-step explanation:
substitute the ordered pair into each equation and ensure that it comes out to be true.
Answer:20
Step-by-step explanation:
