Answer:
2.25
Step-by-step explanation:
2.4 - 0.15
Using place value :
2 = Unit (2 wholes)
4 = tenth place ( 4 tenths)
To subtract 0.15
0 wholes ; 1 tenth ; 5 hundredth
1 tenth can be split into 10 separate hundredths
Hence,
For 2.4
We have ;
2 wholes ; 3 tenths and 10 hundredths
Subtracting 0.15 ;0 wholes ; 1 tenth ; 5 hundredth
(2 - 0) wholes = 2 whole
(3 - 1) tenth = 2 tenth
(10 - 5) hundredth = 5 hundredth
Hence, the difference between (2.4 and 0.15) is :
2 whole ; 2 tenth ; 5 hundredth
Which is equal to : 2.25
Answer:
well the answer is the first one
The smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.
What is the intermediate value theorem?
Intermediate value theorem is theorem about all possible y-value in between two known y-value.
x-intercepts
-x^2 + x + 2 = 0
x^2 - x - 2 = 0
(x + 1)(x - 2) = 0
x = -1, x = 2
y intercepts
f(0) = -x^2 + x + 2
f(0) = -0^2 + 0 + 2
f(0) = 2
(Graph attached)
From the graph we know the smallest positive integer value that the intermediate value theorem guarantees a zero exists between 0 and a is 3
For proof, the zero exists when x = 2 and f(3) = -4 < 0 and f(0) = 2 > 0.
<em>Your question is not complete, but most probably your full questions was</em>
<em>Given the polynomial f(x)=− x 2 +x+2 , what is the smallest positive integer a such that the Intermediate Value Theorem guarantees a zero exists between 0 and a ?</em>
Thus, the smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.
Learn more about intermediate value theorem here:
brainly.com/question/28048895
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Answer:
The answer is 40 minutes, hope this helps