1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Scilla [17]
3 years ago
14

WILL GIVE BRAINLEST!!!

Mathematics
2 answers:
myrzilka [38]3 years ago
8 0

Answer:

A Subtract 87 from 271 and then divide the

difference by 5.75

Step-by-step explanation:

maria [59]3 years ago
6 0

Answer:

Step-by-step explanation:

A. Subtract 87 from 271 and then divide the difference by 5.75

You might be interested in
Which expression is equivalent to 3√32x^8y^10?
denpristay [2]
<span>
3√(32x^8y^10)
= </span><span>3√(16*2 x^8y^10)
= 12x^4y^5 </span>√2

Hope it helps
6 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B0%7D%5E%7B%20%20%5Cpi%20%7D%20%5Ccos%28%20%5Ccot%28x%29%20%20%20%20-%20%2
Nikolay [14]

Replace x with π/2 - x to get the equivalent integral

\displaystyle \int_{-\frac\pi2}^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx

but the integrand is even, so this is really just

\displaystyle 2 \int_0^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx

Substitute x = 1/2 arccot(u/2), which transforms the integral to

\displaystyle 2 \int_{-\infty}^\infty \frac{\cos(u)}{u^2+4} \, du

There are lots of ways to compute this. What I did was to consider the complex contour integral

\displaystyle \int_\gamma \frac{e^{iz}}{z^2+4} \, dz

where γ is a semicircle in the complex plane with its diameter joining (-R, 0) and (R, 0) on the real axis. A bound for the integral over the arc of the circle is estimated to be

\displaystyle \left|\int_{z=Re^{i0}}^{z=Re^{i\pi}} f(z) \, dz\right| \le \frac{\pi R}{|R^2-4|}

which vanishes as R goes to ∞. Then by the residue theorem, we have in the limit

\displaystyle \int_{-\infty}^\infty \frac{\cos(x)}{x^2+4} \, dx = 2\pi i {} \mathrm{Res}\left(\frac{e^{iz}}{z^2+4},z=2i\right) = \frac\pi{2e^2}

and it follows that

\displaystyle \int_0^\pi \cos(\cot(x)-\tan(x)) \, dx = \boxed{\frac\pi{e^2}}

7 0
2 years ago
Helpppppppppppppppppp meeeeeeeeeeeeeeeeeee
DanielleElmas [232]

The fraction computed shows that the cups of sugar that can be used based on the flour will be B. 4 1/2 cups.

<h3>How to calculate the fraction?</h3>

From the information, Jonah used 1 1/2 cups of brown sugar and 2 1/3 cups for flour.

Therefore, the cups of sugar needed will be:

= 1.5/2.33 × 7

= 4.5 = 4 1/2.

Learn more about fractions on:

brainly.com/question/78672

#SPJ1

4 0
2 years ago
Which function is represented by this graph ?
LuckyWell [14K]

Answer:

B

Step-by-step explanation:

its B hope this helpsss

5 0
3 years ago
Read 2 more answers
The Cooper family decided to hike to Hillside Lake, Approximately 8 5/8 miles away. After an hour the lake was still 5 1/3 away.
statuscvo [17]
3 7/24 is the answer for your question
5 0
3 years ago
Read 2 more answers
Other questions:
  • Domain for g(x) = √4x – x^2​
    8·2 answers
  • A quadrilateral<br> with one right angle must be a rectangle<br> A. True<br> B. False
    15·2 answers
  • Sydelle can wax her SUV in 2 hours. Marques can wax the same SUV in 3 hours. If they work together how long will it take them to
    14·1 answer
  • what is the probability that a red or green marble will be selected from a bag containing 9 red marbles, 7 green marbles, and 11
    7·1 answer
  • Ane goes to a juice bar with her friend neil. she is thinking of ordering her favorite drink, 7/8 orange juice and 1/8 cranberry
    12·1 answer
  • If 3a=11b and b= 2c, find the ratio of<br> a:b,<br> a:b:c
    7·1 answer
  • a cell phone company charges $60.00 a month for up to 1 gigabyte of data. the cost of additional data is $0.05 per megabyte. if
    13·2 answers
  • Kinda ez please help aced+
    13·1 answer
  • Tr(n)*2 I NEE HELP ASAP
    7·2 answers
  • How do you add integers with different signs?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!