What is the value of b and c

A civil engineer is designing a public parking lot for the new town hall. The number of cars in each row should be six less than

Alexandra [31]

The new parking lot must hold twice as many cars as the previous parking lot. The previous parking lot could hold 56 cars. So this means the new parking lot must hold 2 x 56 = 112 cars

Let y represent the number of cars in each row, and x be the number of total rows in the parking lot. Since the number of cars in each row must be 6 less than the number of rows, we can write the equation as:

y = x - 6 (1)

The product of cars in each row and the number of rows will give the total number of cars. So we can write the equation as:

xy = 112 (2)

Using the above two equations, the civil engineer can find the number of rows he should include in the new parking lot.

Using the value of y from equation 1 to 2, we get:

x(x - 6) = 112 (3)

This equation is only in terms of x, i.e. the number of rows and can be directly solved to find the number of rows that must in new parking lot.

6 0

2 years ago

How many solutions does the equation 4x + 8 = −2 − 2 + 5x have? (5 points) Two One None Infinitely many

djverab [1.8K]

Answer:

just one solution

Step-by-step explanation:

4x + 8 = −2 − 2 + 5x

4x - 5x = -2 - 2 - 8

x = 12

6 0

2 years ago

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Solve the system by substitution x=-8y-15 2x+5y=-8

Ghella [55]

To solve this system by substitution, we must substitute in the value we are given for x in terms of y (the first equation) into the second equation. This is modeled below:

x = -8y - 15

2x + 5y = -8

2 (-8y - 15) + 5y = -8

Now, we should solve this new equation for y. To begin, we should use the distributive property to get rid of the parentheses on the left side of the equation and begin the simplification process.

-16y - 30 + 5y = -8

Next, we can combine like terms on the left side of the equation by adding together the two terms that both contain the variable y.

-11y - 30 = -8

Next, we should add 30 to both sides in order to move all of the constant (number) terms to the left side of the equation.

-11y = 22

After that, we should divide both sides of the equation by -11 in order to get the variable y alone.

y = -2

Now, we can substitute our value for y back into one of our original equations (it doesn't matter which one you choose; they will yield the same answer).

x = -8y - 15

x = -8(-2) - 15

To simplify, we should following the order of operations outlined by PEMDAS and compute the multiplication and then the subtraction.

x = 16 - 15

x = 1

Therefore, the answer to the system is x = 1 and y = -2, or (1,-2) when written as an ordered pair.

Hope this helps!

3 0

2 years ago

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Write an equation of the line containing the point (3,5) and perpendicular to the line 4x-3y=5

ICE Princess25 [194]

Answer:

Step-by-step explanation:

In order to write the equation of the line perpendicular to the given line, we first have to know what the slope of the given line is, and there's no way to tell by looking at it in its current form, which is standard. We need to solve that equation for y to determine the slope of that line. Solving for y:

$-3y=-4x+5$ and

3y = 4x - 5 (just change all the signs so our y term isn't negative anymore...yes, you're "allowed" to do that!) and

$y=\frac{4}{3}x-\frac{5}{3}$ So we can see now that the slope of this line is 4/3. That means that the perpendicular slope is -3/4. Passing through the given point (3, 5):

$y-5=-\frac{3}{4}(x-3)$ * and

$y-5=-\frac{3}{4}x+\frac{9}{4}$ and

$y=-\frac{3}{4}x+\frac{9}{4}+\frac{20}{4}$ so

$y=-\frac{3}{4}x+\frac{29}{4}$ ** and, in standard form:

4y = -3x + 29 and

3x + 4y = 29***

* : point-slope form

** : slope-intercept form

*** : standard form

3 0

2 years ago

Please Help!!<br><br>Use Euler’s formula to write in exponential form.

LekaFEV [45]

Answer:

C, $4e^{i(7\pi/4)}$

Step-by-step explanation:

To remind you, Euler's formula gives a link between trigonometric and exponential functions in a very profound way:

$e^{ix}=\cos{x}+i\sin{x}$

Given the complex number $2\sqrt{2}-2i\sqrt{2}$ , we want to try to get it in the same form as the right side of Euler's formula. As things are, though, we're unable to, and the reason for that has to do with the fact that both the sine and cosine functions are bound between the values 1 and -1, and 2√2 and -2√2 both lie outside that range.

One thing we could try would be to factor out a 2 to reduce both of those terms, giving us the expression $2(\sqrt{2}-i\sqrt{2})$

Still no good. √2 and -√2 are still greater than 1 and less than -1 respectively, so we'll have to reduce them a little more. With some clever thinking, you could factor out another 2, giving us the expression $4\left(\frac{\sqrt{2}}{2} -i\frac{\sqrt{2}}{2}\right)$ , and <em>now </em>we have something to work with.

Looking back at Euler's formula $e^{ix}=\cos{x}+i\sin{x}$ , we can map our expression inside the parentheses to the one on the right side of the formula, giving us $\cos{x}=\frac{\sqrt2}{2}$ and $\sin{x}=-\frac{\sqrt2}{2}$ , or equivalently:

$\cos^{-1}{\frac{\sqrt2}{2} }=\sin^{-1}-\frac{\sqrt2}{2} =x$

At this point, we can look at the unit circle (attached) to see the angle satisfying these two values for sine and cosine is 7π/4, so $x=\frac{7\pi}{4}$ , and we can finally replace our expression in parentheses with its exponential equivalent:

$4\left(\frac{\sqrt2}{2}-i\frac{\sqrt2}{2}\right)=4e^{i(7\pi/4)}$

Which is c on the multiple choice section.

4 0

3 years ago