Y=18-7x/-4
gradient = 7/4
parallel lines, same gradient.
y--7=7/4(x-2)
y=7x-14-28/4
y= (7x + 14)/4
What’s the full question?
Note that a squared pyramid has a square base & 4 equal triangles.
To find the lateral the lateral area you calculate the area of the 4 equal triangles and to find the surface area (total Area) you add the area of the base:
Area of each triangle = side (5) x slant (9) and you divide by 2
==>Aera of 1 triangle = (9x5)/2 = 45/2 & for the 4 triangles
Lateral area = (45/2) x 4 = 90 in²
Now the base area (square) = 5 x 5= 25 in²
so the surface area = 90+25 = 115 in² (answer a)
Answer:
x = 12
y = 22
Total amount = $2596
Step-by-step explanation:
First let's find the value of each deposit until the 10th in relation to x and y:
1st: x
2nd: y
3rd: x + y
4th: x + 2y
5th: 2x + 3y
6th: 3x + 5y
7th: 5x + 8y
8th: 8x + 13y
9th: 13x + 21y
10th: 21x + 34y
Now, we can write a system with two equations and two variables:
2x + 3y = 90
21x + 34y = 1000
From the first equation: x = (90 - 3y)/2
Using this value of x in the second equation, we have:
21*(90 - 3y)/2 + 34y = 1000
945 - 31.5y + 34y = 1000
2.5y = 55
y = 22
Now we can find x:
x = (90 - 3*22)/2 = 12
Now, summing all the deposits, we have a total of 55x + 88y, which is equal to 55*12 + 88*22 = $2596
