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3 years ago

In a group of dogs and their owners, there are exactly 20 heads and 64 legs. How many dogs are in the group

Mathematics

1 answer:

Juliette [100K]3 years ago

8 0

Answer:

If we assume that everyone in the group is an owner, we would have

$20*2=40$ legs.

$64-40=24$ legs

Therefore, we need 24 more legs.

These 24 additional legs can be made from the difference of legs between the owners and dogs.

In this case, dogs have $4-2=2$ more legs than an owner.

24 ÷ 2 = 12.

There are 12 dogs in the group.

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Find the probability that when a couple has three children, at least one of themis a girl. (Assume that boys and girls are equal

kvv77 [185]

Answer: $\bold{\dfrac{7}{8}=87.5\%}$

Step-by-step explanation:

"At least one girl" means P(1 girl) + P(2 girls) + P(3 girls) or 1 - P(all boys)

I will use the latter: 1 - P(all boys)

P(all boys) = $\dfrac{1}{2}\times \dfrac{1}{2}\times \dfrac{1}{2}=\dfrac{1}{8}$

$1 - P(all\ boys) \quad = \quad 1-\dfrac{1}{8}\quad =\large\boxed{\dfrac{7}{8}}$

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3 years ago

George bought socks for "$"300 and planned to sell them for $6 a pair. write an inequality to find the minimum number of socks h

Anit [1.1K]

The inequality 6s - 300 > 210 represents the minimum number of socks (s) when George bought socks for "$"300 and planned to sell them for $6 a pair, and want to make a profit of more than 210.

In the question, we are given that George bought socks for $300.

Therefore, George's total cost = $300.

We assume the number of pairs of socks George sells to be s.

The unit price per pair quoted by George = $6

Therefore, George's total sales = $6s.

We know that the profit over a transaction is given as the difference between sales and costs, that is,

The profit = The total sales - the total costs,

or, profit = 6s - 300.

In the question, we are required to make a profit of more than 210.

This can be shown by the inequality,

6s - 300 > 210.

Thus, the inequality 6s - 300 > 210 represents the minimum number of socks (s) when George bought socks for "$"300 and planned to sell them for $6 a pair, and want to make a profit of more than 210.

Learn more about inequalities at

brainly.com/question/24372553

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2 years ago

find two consecutive odd integers whose product is 1 less than 6 times their sum. Domain for the smallest : {-1, 1, 11}

inn [45]

Let x be the 1st odd number, and x+2 the second odd consecutive number:

(x)(x + 2) = 6[((x) + (x+2)] -1
x² + 2x = 6(2x + 2) - 1

x² + 2x = 12x +12 - 1
And x² - 10x - 11=0

Solve this quadratic expression:

x' = [+10 +√(10²- 4.(1)(-11)]/2 and x" = [+10 -√(10²- 4.(1)(-11)]/2

x' = [10 + √144]/2 and x" = [10 - √64]/2

x' = (10+12)/2 and x" = (10-12)/2

x = 11 and x = -1

We have 2 solutions that satisfy the problem:

1st for x = 11, the numbers at 11 and 13
2nd for x = - 1 , the numbers are -1 and +1
If you plug each one in the original equation :(x)(x + 2) = 6[((x) + (x+2)] -1
you will find that both generates an equlity

6 0

3 years ago

At which root does the graph of f(x) = (x – 5)3(x + 2)2 touch the x-axis?

Sauron [17]

Answer:

x = -2

Step-by-step explanation:

The root will touch the axis and bounce off when the exponent is even. In that case, that means (x + 2)² is the binomial that will bounce. Therefore, the root which bounces and touches the x-axis is x = -2.

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3 years ago

Jessica is baking a cake. The recipe says that she has to mix 96 grams of sugar into the flour. Jessica knows that 1 cup of this

d1i1m1o1n [39]

She added 64 grams which is 34 grams less than Wat was needed

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3 years ago

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