The given function is a variable separable differential equation. Combine like terms, integrate, apply the appropriate limits, and express V in terms of t. This is done as follows:
dV/dt = -3(V)^1/2
dV/-3V^1/2 = dt
m here is the initial V which is 225. Then after integrating,
-2/3 (√V - √225) = t
-2/3 (√V - 15) = t
That is the expression for V at time t. I hope I was able to help. Have a good day.
Answer:Yes, I checked.. it is option 2
Step-by-step explanation:
Answer:
C. 2.
Step-by-step explanation:
The graph descends from the left so the coefficient of the leading term is negative. It is also a cubic equation with zeros of -20, about 6.5 and about 13. so we can write the equation as below. The last 2 values can only be guessed because the x axis only shows values which are multiples of 5.
f(x) = a(x + 20)(x - 6.5)(x - 13) where a is a negative constant.
(This is only an approximation).
By the Remainder theorem, when the expression is divided by (x + 10):
f(-10) = -20 so we have
-20 = a (-10 + 20)(-10-6.5)(-10 - 13)
(10)(-16.5)(-23)a = -20
a = -20 / (10)(-16.5)(-23)
a = -0.0053
When the equation is divided by (x - 10) then f(10) is the remainder so substituting we have as the remainder:
-0.0053(10+20)(10-6.5)(10 -13)
-0.0053 * 30 * 3.5 * -3
= 1.7 approximately.
Looks like the answer is 2.
