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zysi [14]
3 years ago
11

Click the square near each correct choice to fill it in. Be sure to mark all correct answers.

Mathematics
1 answer:
Bumek [7]3 years ago
3 0

Answer:

The correct options are;

A. 1·2 = 2

B. 1·1 = 1

E. 1 + 1 = 2

Step-by-step explanation:

Given that the equations 1.2 = 2 and 1.1 = 1 are correctly written as 1·2 = 2 and 1·1 = 2, we have;

The product of any number and one is equal the same number, that is a × 1 = a

Whereby we have the expression 1·2 which is 1 × 2,  we therefore have;

1 × 2 = 1 · 2= 2

B. Similarly we have;

1 · 1 = 1 × 1 = 1

Also, 1 + 1 = 2 is correct as the sum of two numbers is equal to the sum of the count of the numbers, therefore;

E. 1 + 1 = 2 is correct.

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Find f(-3) if f(x) = x 2.
vlabodo [156]

Answer:

f(-3) = 9

Step-by-step explanation:

Lets define f(a) first where a is any integer,

f(a) is found out by putting the integer in the function in place of the variable

So for the given question

f(x) = x^{2}

In order to find f(-3) we will put -3 in place of x

So putting -3,

f(-3) = (-3)^{2}

f(-3) = 9

So, the value of function at -3 is 9 ..

5 0
3 years ago
Read 2 more answers
Discrete R.V. Assume a student shows up for EGR 280 completely unprepared and the instructor gives a pop quiz. Assume there are
Tom [10]

Answer:

a) p=0.2

b) probability of passing is 0.01696

.

c) The expected value of correct questions is 1.2

Step-by-step explanation:

a) Since each question has 5 options, all of them equally likely, and only one correct answer, then the probability of having a correct answer is 1/5 = 0.2.

b) Let X be the number of correct answers. We will model this situation by considering X as a binomial random variable with a success probability of p=0.2 and having n=6 samples. We have the following for k=0,1,2,3,4,5,6

P(X=k) = \binom{n}{k}p^{k}(1-p)^{n-k} = \binom{6}{k}0.2^{k}(0.8)^{6-k}.

Recall that \binom{n}{k}= \frac{n!}{k!(n-k)!} In this case, the student passes if X is at least four correct questions, then

P(X\geq 4) = P(X=4)+P(X=5)+P(X=6)=\binom{6}{4}0.2^{4}(0.8)^{6-4}+\binom{6}{5}0.2^{5}(0.8)^{6-5}+\binom{6}{6}0.2^{6}(0.8)^{6-6}= 0.01696

c)The expected value of a binomial random variable with parameters n and p is E[X] = np. IN our case, n=6 and p =0.2. Then the expected value of correct answers is 6\cdot 0.2 = 1.2

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3 years ago
When renting a limo for prom, the number of people varies inversely with the cost per person. Originally there were 12 people an
pashok25 [27]
The answer would be $10.
8 0
3 years ago
PLZ do this!!! I will give brainliest to anyone who does them all right. I need this done at 3:30 (it 2:44 right now)! No fake a
leva [86]

Answer:

A: y=1/3x+5

B: y=-2x+9

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F:y=x-2

#1 rodney's error for

y=30x+10 is that he started off at 30 but he had to start off at 10 so it starts at (0,10) (1,40) (2,70) and keep going on by adding one to the x value and 30 to the y value

#2 rodneys error for

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#3 Rodneys error for

y=x-2 is that he didn't start at (0.-2)

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Step-by-step explanation:

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3 years ago
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Which of the following is an element?
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