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sesenic [268]
3 years ago
5

PLZ do this!!! I will give brainliest to anyone who does them all right. I need this done at 3:30 (it 2:44 right now)! No fake a

nswers, links, or "I don't know".
As you can tell from the 50 points, this means a lot to me.

Mathematics
2 answers:
Sonbull [250]3 years ago
7 0

Answer:

first page-

a)y=-3

b)y=x-2

sorry that's all i can help with

Step-by-step explanation:

you use rise/run

wishing you the best of luck :)

hopefully, this helps

have a splendid day!!

leva [86]3 years ago
5 0

Answer:

A: y=1/3x+5

B: y=-2x+9

C: y=-3

D:y=2x+9

E: y=-10x+80

F:y=x-2

#1 rodney's error for

y=30x+10 is that he started off at 30 but he had to start off at 10 so it starts at (0,10) (1,40) (2,70) and keep going on by adding one to the x value and 30 to the y value

#2 rodneys error for

y=-1/2x+5 is that he went up by 1/2 instead of going down. it's a negative 1/2 so he had to go down

#3 Rodneys error for

y=x-2 is that he didn't start at (0.-2)

I'm not sure about the last picture but i think that it's

Tierra, Sharayah, Caleb, and Lang

Step-by-step explanation:

You might be interested in
How do you solve this??? I need it fast please help with steps.<br> (x+3)(x+1)^2(x−4)&gt;0
scZoUnD [109]

Answer:

  x < -3 or x > 4

Step-by-step explanation:

The product of the factors is 4th-degree, and the leading coefficient is 1 (positive).

The factors tell you the following about the zeros:

  x = -3 . . . sign change from + to -

  x = -1 . . . graph touches, but no sign change. - on either side of x=-1

  x = 4 . . . sign change from - to +

__

The function will be positive for x < -3 and for x > +4.

_____

<em>Additional comments</em>

The value of the function is zero when any of its factors is zero. The value of a factor changes sign when the value of x changes from one side of the 0 to the other. For example, here, we have x+1 as a factor, so x=-1 is a zero. When x = -0.9, the factor is positive (-0.9 +1 = 0.1). When x = -1.1, the factor is negative (-1.1 +1 = -0.1). If this factor were to the first power, it would cause the value of the function to change sign at x=-1.

However, the factor (x+1) has an even power: (x+1)^2. That means when the factor is negative, its square is positive, and when the factor is positive, its square is positive. In short, the factor (x+1)^2 causes the function to be zero at x=-1, but does not make the function change sign there.

The product of all of these factors will result in a polynomial with x^4 as the highest-degree term. That means the function is of even degree. The leading coefficient is 1, so is positive, and the function will generally have a U-shape. The left-most (odd-degree) zero will be where the function changes sign from positive to negative. The right-most (odd-degree) zero will be where the function changes sign from negative to positive. Those zeros are x=-3 and x=+4, respectively. There are no places between these where the function changes sign, so these zeros are the ends of the regions where the function is positive (>0).

3 0
3 years ago
Please help me with this
Brilliant_brown [7]

Answer:

1080

Step-by-step explanation:

4 0
3 years ago
If the answer is correct ill make give you brainliest answer!
liberstina [14]

Answer:

Step-by-step explanation:

Not sure if it was the question they asked buttt....

6 0
3 years ago
Need this for homework plz help me
solong [7]

Answer:

7. -700

8. C

9. 1206

Hope this helps.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What's the answer ??????
photoshop1234 [79]
M&0 are similar but not congruent

3 0
3 years ago
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