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3 years ago

Solve for x. Round to the nearest tenth.

Mathematics

1 answer:

vlabodo [156]3 years ago

3 0

Answer:

Step-by-step explanation:

just took it

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I don't get it It like like realllllllly hard

luda_lava [24]

Find the difference between x and y, so 3 and 27, the difference is 9. To see if its constant, put it into 9*8, which is 72, so the constant is 9. To find the answer in the blanks, plug in 9 and the number to find the answer.

6 0

3 years ago

Read 2 more answers

According to the Square Root property of Equations, the solution set of x2 = 25 is {±5}.

Gala2k [10]

Justify "x2 = 25 is {±5}"

First, please write x^2, not x2.

x^2 = 25; solve for x. Take the sqrt of both sides. Must write "plus or minus " in front of the sqrt of 25:

x^2 = 25 becomes x = plus or minus 5, so x: {-5, 5}

7 0

4 years ago

4. Both the Galapagos Islands and the island of Naura are on the Equator, but the Galapagos Islands are at 90.30◦W whereas the i

nordsb [41]

Answer:

Distance between Nauru and Galapagos islands = 11525 Km to the nearest Km

Step-by-step explanation:

The angle between the two Islands is given as X

X = (180 - 166.56) + (180 - 90.30)

X = 13.44° + 89.70°

X = 103.14

Distance between the islands = length of the arc with angle X subtended at the center of the earth of radius R.

Length of arc = (X/360) × 2πR

Where, R, radius of the earth = 6400 Km

Length of arc = (103.14/360) × 2π × 6400 Km

Length of arc = 11525.48 Km

Therefore, distance between Nauru and Galapagos islands = 11525 Km to the nearest Km

3 0

4 years ago

Are -1,0,1,2 infinite or finite numbers

Serggg [28]

Answer:

Infinite

Step-by-step explanation:

3 0

4 years ago

A person must score in the upper 7% of the population on an admissions test to qualify for membership in society catering to hig

olya-2409 [2.1K]

Answer:

The minimum score a person must have to qualify for the society is 162.05

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Test scores are normally distributed with a mean of 140 and a standard deviation of 15. This means that $\mu = 140, \sigma = 15$ .