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2 years ago

Unit Test Review

Mathematics

1 answer:

Mrrafil [7]2 years ago

6 0

825 miles to drive 15 hours

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Two of the golf scores at the local tournament were unreadable, but the mean score was 85 and the lowest score was 75. if the re

Vika [28.1K]

Step-by-step explanation:

Assuming the readable scores are:

100, 82, 95, __ , 90, 81, 75, 83, __

We know the mean (or average) is 85, so:

85 = (100 + 82 + 95 + x + 90 + 81 + 75 + 83 + y) / 9

765 = 606 + x + y

159 = x + y

We know the lowest score is 75, so x and y must be at least 76. Possible answers are:

76 and 83

77 and 82

78 and 81

79 and 80

80 and 79

81 and 78

82 and 77

83 and 76

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2 years ago

In a set of real numbers, the first number less then -3 is -4 true or false

Annette [7]

Answer:

true

Step-by-step explanation:

the bigger the number of a negative integer, the smaller the value become

8 0

3 years ago

Read 2 more answers

Which statements are true about the fully simplified product of (b-2c)(-3b+c? Select two options.

SSSSS [86.1K]

Answer:

C) The simplified product has a degree of 2.

F) The simplified product, in standard form, has exactly 2 negative terms.

Step-by-step explanation:

5 0

3 years ago

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Find the value of the question mark

pogonyaev

Answer:

4.88

Step-by-step explanation:

4 0

2 years ago

50 points! I understand A. and B. but I would really appreciate help with C.

FromTheMoon [43]

Answer:

$51.72\text{ cells per hour}$

Step-by-step explanation:

So, the function, P(t), represents the number of cells after t hours.

This means that the derivative, P'(t), represents the instantaneous rate of change (in cells per hour) at a certain point t.

So, we are given that the quadratic curve of the trend is the function:

$P(t)=6.10t^2-9.28t+16.43$

To find the instanteous rate of growth at t=5 hours, we must first differentiate the function. So, differentiate with respect to t:

$\frac{d}{dt}[P(t)]=\frac{d}{dt}[6.10t^2-9.28t+16.43]$

Expand:

$P'(t)=\frac{d}{dt}[6.10t^2]+\frac{d}{dt}[-9.28t]+\frac{d}{dt}[16.43]$

Move the constant to the front using the constant multiple rule. The derivative of a constant is 0. So:

$P'(t)=6.10\frac{d}{dt}[t^2]-9.28\frac{d}{dt}[t]$

Differentiate. Use the power rule:

$P'(t)=6.10(2t)-9.28(1)$

Simplify:

$P'(t)=12.20t-9.28$

So, to find the instantaneous rate of growth at t=5, substitute 5 into our differentiated function:

$P'(5)=12.20(5)-9.28$

Multiply:

$P'(5)=61-9.28$

Subtract:

$P'(5)=51.72$

This tells us that at exactly t=5, the rate of growth is 51.72 cells per hour.

And we're done!

7 0

2 years ago