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Tems11 [23]
3 years ago
10

Plzzz help m ASAP because I need help

Mathematics
1 answer:
Bond [772]3 years ago
7 0
The answer is A. I got this answer by crossing out the possibilities. 90 degrees and 60 degrees are too short and 180 degrees is too long.
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You roll a pair of number cubes.What is the probability of getting even numbers on both cubes?
andreev551 [17]

Answer:

1/4 or 25%

Step-by-step explanation:

Let's see, we want to know probability of an event in which we roll two even numbers.

"We know that probability is defined as number of desired outcomes divided by all possible outcomes"

e - even number

o - odd number

our desired outcome: (e, e) total of 1

all possible outcomes: (e, e), (e, o), (o, e), (o,o) total of 4

that gives us 1/4

8 0
4 years ago
someone help before I give up my life. Thanks.
oksian1 [2.3K]

Answer:

I think that its x^2 + y^2 = 0.

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7 0
2 years ago
Suppose that 13 inches of wire costs 65 cents. At the same rate, how many inches of wire can be bought for 45 cents?
Lina20 [59]
9 because 13/.65 = 20 x .45 = 9
4 0
3 years ago
The position of a sprinter at the starting blocks is shown in the diagram. Given that the sprinter starts on level ground, which
pav-90 [236]
The correct anwser is a . but u could try to prove b and c but a is true 

8 0
3 years ago
Two altitudes of a triangle have lengths $12$ and $14$. What is the longest possible integer length of the third altitude
nataly862011 [7]

The longest possible altitude of the third altitude (if it is a positive integer) is 83.

According to statement

Let h is the length of third altitude

Let a, b, and c be the sides corresponding to the altitudes of length 12, 14, and h.

From Area of triangle

A = 1/2*B*H

Substitute the values in it

A = 1/2*a*12

a = 2A / 12 -(1)

Then

A = 1/2*b*14

b = 2A / 14 -(2)

Then

A = 1/2*c*h

c = 2A / h -(3)

Now, we will use the triangle inequalities:

  • a < b+c

2A/12 < 2A/14 + 2A/h

Solve it and get

h<84

  • b < a+c

2A/14 < 2A/12 + 2A/h

Solve it and get

h > -84

  • c < a+b

2A/h < 2A/12 + 2A/14

Solve it and get

h > 6.46

From all the three inequalities we get:

6.46<h<84

So, the longest possible altitude of the third altitude (if it is a positive integer) is 83.

Learn more about TRIANGLE here brainly.com/question/2217700

#SPJ4

8 0
2 years ago
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