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finlep [7]
2 years ago
15

Find the domain and range of the function: f(x) =5-x-3 to the square root Domain: Range:

Mathematics
2 answers:
defon2 years ago
8 0

Answer:

Edgenuity 2020

Step-by-step explanation:

mario62 [17]2 years ago
6 0
Domain: ( -infinity, infinity ) , { x|x € R }
Range: ( -infinity, infinity ) , { y|y € R }
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Which of the following equations have infinitely many solutions? Choose all answers that apply: A 6x + 35 = –60 – 35 -6x + 35 =
frozen [14]

Answer:

The answer is C because they have the same coefficient and variable on both sides (or something like that but its definitely c )

5 0
2 years ago
Help I need this to help me get a grade 9
MrMuchimi

Answer:

83

Step-by-step explanation:

the angle with 126 is supplementary and all the angles of the triangle are supplementary

180-126 = 54

54 + 43 = 97

180 - 97 = 83

6 0
2 years ago
A football team tries to move the ball forward as many yards as possible on each play, but sometimes they end up behind where th
Illusion [34]

Answer:

Given:

The distances, in yards, that a team moves on its first five plays are 2, 21, 4, 3, and 25.

Solved:

1. The greatest number is 25

2. If the moved distances are square, which one is largest?

3. The move which is greater than 4 is considered "big play"

=> 21 and 25 are big play (21 > 4, 25 > 4)

Hope this helps!

:)

3 0
3 years ago
I need help with this problem
Arada [10]

Answer:

65.56°

Step-by-step explanation:

We know that if we take dot product of two vectors then it is equal to the product of magnitudes of the vectors and cosine of the angle between them

That is let p and q be any two vectors and A be the angle between them

So, p·q=|p|*|q|*cosA

⇒cosA=\frac{u.v}{|u||v|}

Given u=-8i-3j and v=-8i+8j

|u|=\sqrt{(-8)^{2}+ (-3)^{2}} =8.544

|v|=\sqrt{(-8)^{2}+ (8)^{2}} =11.3137

let A be angle before u and v

therefore, cosA=\frac{u.v}{|u||v|}=\frac{(-8)*(-8)+(-3)*(8)}{8.544*11.3137} =\frac{40}{96.664}

⇒A=arccos(\frac{40}{96.664} )=arccos(0.4138 )=65.56

Therefore angle between u and v is 65.56°

5 0
2 years ago
PLEASE HELP!! Compare & Contrast how Completing the Square is used to Convert a quadratic function to vertex form with how i
Likurg_2 [28]

Answer:

Step-by-step explanation:

Given a general quadratic formula given as ax²bx+c = 0

To generate the general formula to solve the quadratic equation, we can use the completing the square method as shown;

Step 1:

Bringing c to the other side

ax²+bx = -c

Dividing through by coefficient of x² which is 'a' will give:

x²+(b/a)x = -c/a

- Completing the square at the left hand side of the equation by adding the square of half the coefficient x i.e (b/2a)² and adding it to both sides of the equation we have:

x²+(b/a)x+(b/2a)² = -c/a+(b/2a)²

(x+b/2a)² = -c/a+(b/2a)²

(x+b/2a)² = -c/a + b²/4a²

- Taking the square root of both sides

√(x+b/2a)² = ±√-c/a + b²/√4a²

x+b/2a = ±√(-4ac+b²)/√4a²

x+b/2a =±√b²-4ac/2a

- Taking b/2a to the other side

x = -b/2a±√√b²-4ac/2a

Taking the LCM:

x = {-b±√b²-4ac}/2a

This gives the vertex form with how it is used to Solve a quadratic equation.

7 0
2 years ago
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