Slove for the value of x to the nearest whole number?

. Darlene is making punch. She pours 4 quarts 2 cups of apple juice into a bowl. Then she pours 3 quarts 1 cup of grape juice in

pshichka [43]

Answer:

C. 7 quarts 3 cups

Step-by-step explanation:

First you add 4 quarts, with 3 quarts to get 7 quarts. Then, you add 1 cup with 2 cups to get 3 cups.

8 0

3 years ago

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What 34.1 divided equals 22

Artyom0805 [142]

34.1 ÷ __ = 22
So lets think if we wanna find the missing number we have to divide 34.1 and 22 to get 1.55
So, the final answer is
34.1 ÷ 1.55 = 22
I hope this has helped!

6 0

3 years ago

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Evaluate the expression. Choose the best answer. <img src="https://tex.z-dn.net/?f=8%5EP4" id="TexFormu

Morgarella [4.7K]

N P r = (n!)/((n-r)!)
8 P 4 = (8!)/((8-4)!)
8 P 4 = (8!)/(4!)
8 P 4 = (8*7*6*5*4!)/(4!)
8 P 4 = 8*7*6*5
8 P 4 = 1680

The final answer is 1680

4 0

3 years ago

the larger of two number is nine more than four times the smaller number. the sum of the two numbers is fifty-nine. find the two

VLD [36.1K]

This is solved by setting up two equations and then using one to answer the other.
The first step (use what is given to set up the two separate equations)
We are looking for two numbers, let us call them X and Y.
We are told that X + Y = 59
We are also told that (9 more than) 9+ (4times the smaller number) 4Y is the bigger number X
Then we combine that into 9+4Y=X
so we now have two separate equations and we can use one to solve the other. Everywhere we have X in the first equation, we will fill in with the second equation
(9+4Y) +Y = 59 [then combine like terms]
9+5Y=59 [subtract 9 from both sides]
5Y=50 [divide both sides by 5 to isolate the Y]
Y=10 [now plug this into either equation to solve for X]
9+4(10)=X
9+40=X
49=X and 10=Y

4 0

3 years ago

What is the sum or difference?

dlinn [17]

1. Ans: Option (B) $-6x^4$

Explanation:
Given: $2x^4 - 8x^4$
Take the common out:
=> $x^4(2 - 8)$

Hence: => $[tex]-6x^4$ [/tex] (Option B)

2. Ans: Option (D) $-3y^5$

Explanation:
Given: $6y^5 - 9y^5$
Take the common term(s) out:
=> $y^5(6-9)$

Hence: => $-3y^5$ (Option D)

3. Ans: Option (B) $9x^2 - 12x + 6$ quadratic trinomial

Explanation:
Given: $6 - 12x + 13x^2 - 4x^2$

The standard form of polynomial function must have the highest powered value at the start, then the second highest and so on.

=> $13x^2 - 4x^2 - 12x + 6$
=> $9x^2 - 12x + 6$ (Option B)

4. Ans: Option (C) $7.3x^2 + 0.8x + 1.3$

Explanation:
In order to find the total number of Common and Endler's guppies, you need to add both Common and Endler's guppies' polynomials, as follows:

Common guppies: $3.1x^2 +6.0x + 0.3$ 
Endler's guppies: $4.2x^2 - 5.2x + 1.0$
(add both)
-----------------------------------------------------------------
Total number: $7.3x^2 +0.8x + 1.3$
-----------------------------------------------------------------
Hence the ans is Option(C) $7.3x^2 + 0.8x + 1.3$

5. Ans: Option (D) $2x^2(133 - 18 \pi )$

Explanation:
First let's find the total area of the yard:
Total Area of the Yard = 14x * 19x = $266x^2$

Now the area of the circular fountain:
Area of the Circular Fountain = $\pi r^2$
Since, r=6x
Therefore,
Area of the Circular Fountain = $\pi (6x)^2 = 36 \pi x^2$

Now the final Area of the yard would be:
Final area of the Yard = Total Area of the Yard - Area of the Circular Fountain
Final area of the Yard = $266x^2$ - $36 \pi x^2$
=> Final area of the Yard = $2x^2(133 - 18 \pi)$ (Option D)

6. Ans: Option (A) $56x^2$

Explanation:
First let's find the total area of the lot:
Total Area of the lot= 6x * 10x = $60x^2$

Now the area of the stadium:
Area of the stadium = 1x * 4x = $4x^2$

Now the final Area of the lot would be:
Final area of the lot= Total Area of the lot - Area of the stadium
Final area of the lot= $60x^2$ - $4x^2$
=> Final area of the lot = $56x^2$ (Option A)

-i

4 0

3 years ago

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