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Debora [2.8K]
3 years ago
11

How do I write an equation for a line with these coordinates (3,25) (4,31)

Mathematics
1 answer:
lara [203]3 years ago
4 0
M = 25 - 31 / 3 - 4
m = - 16 / - 1
m = 16

25 = 16(3) + c
c = 25 - 48
c = - 23
y = 16x - 23
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Idenify the numbers that are located below -3.5 on a vertical number line
belka [17]

A number line is just that – a straight, horizontal line with numbers placed at even increments along the length. The numbers that are located below -3.5 on a vertical number line are (-∞,-3.5).

<h3>What is a number line?</h3>

A number line is just that – a straight, horizontal line with numbers placed at even increments along the length. It’s not a ruler, so the space between each number doesn’t matter, but the numbers included on the line determine how it’s meant to be used.

The numbers that are located below -3.5 on a vertical number line are all the numbers that are less than -3.5. The numbers that are located below -3.5 on a vertical number line are (-∞,-3.5).

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Equivalent Fractions
Maru [420]

C is the correct answer


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Evaluate –3ab when a = –2 and b = –5.
UNO [17]
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3 years ago
Equation using the quadratic fromula for 0.05x^2 + 1.1x = 250
Anuta_ua [19.1K]

Answer:

x=60.56, x=-82.56

Step-by-step explanation:

Solve using quadratic formula

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x=\frac{-b+-\sqrt{b^2-4ac}}{2a}

0.05x^2 + 1.1x = 250

Subtract 250 on both sides

0.05x^2 + 1.1x - 250=0

a= 0.05, b=1.1 , c=-250

Plug in the values in the formula

x=\frac{-1.1+-\sqrt{(1.1)^2-4(0.05)(-250)}}{2(0.05)}

x=\frac{-1.1+-7.156116265}{0.1}

Now make two equations , one with +  and one with -

then we solve for x

x=\frac{-1.1+7.156116265}{0.1}

x=60.56

x=\frac{-1.1-7.156116265}{0.1}

x=-82.56


3 0
3 years ago
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