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Ber [7]
3 years ago
8

Mndsndfbabndfbsdjfbhsadfbnnsd

Mathematics
1 answer:
enyata [817]3 years ago
5 0
This year, the year is 2021
You might be interested in
3p . (2+k) = 6p + 3pk
pashok25 [27]
3p* (2+k) = 6p + 3pk

Subtract 6 p + 3 pk from the both sides:

3p(2+k) -(6p+3pk) = 6p+3pk-(6p+3pk)

= 3pk(2+k) - 6p-3pk = 0

Factor 3p(2+k) - 6p - 3k

Factor out common term 3p

= 3p(k-k+2-2)

refine:

0 = 0

true for all p

hope this helps!
3 0
3 years ago
Find the smallest value of k when 280 is a perfect square
alexandr402 [8]

Answer:

i don't know do you play free fire

4 0
2 years ago
Can someone explain to me #2 I only need #2
elena-s [515]

Answer:

in a rectangle, opposite sides are equal in length

Step-by-step explanation:

now in this question, Pythagoras theorem is being used to find the length

we know both sides by using Pythagoras theorem find third side and get the sum to find ac+bd

5 0
2 years ago
Read 2 more answers
Of 1000 randomly selected cases of lung cancer, 823 resulted in death within 10 years.
Arada [10]

Answer:

a) 0.823 - 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.799

0.823 + 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.847

The 95% confidence interval would be given by (0.799;0.847)

b) n=\frac{0.823(1-0.823)}{(\frac{0.03}{1.96})^2}=621.79  

And rounded up we have that n=622

c) n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11  

And rounded up we have that n=1068

Step-by-step explanation:

Part a

\hat p=\frac{823}{1000}=0.823

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.823 - 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.799

0.823 + 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.847

The 95% confidence interval would be given by (0.799;0.847)

Part b

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.03 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.823(1-0.823)}{(\frac{0.03}{1.96})^2}=621.79  

And rounded up we have that n=622

Part c

n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11  

And rounded up we have that n=1068

5 0
3 years ago
Help with this problem pls
Yuki888 [10]

Answer:

question is not clear please send again

3 0
3 years ago
Read 2 more answers
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