Start with 180.
<span>Is 180 divisible by 2? Yes, so write "2" as one of the prime factors, and then work with the quotient, 90. </span>
<span>Is 90 divisible by 2? Yes, so write "2" (again) as another prime factor, then work with the quotient, 45. </span>
<span>Is 45 divisible by 2? No, so try a bigger divisor. </span>
<span>Is 45 divisible by 3? Yes, so write "3" as a prime factor, then work with the quotient, 15 </span>
<span>Is 15 divisible by 3? [Note: no need to revert to "2", because we've already divided out all the 2's] Yes, so write "3" (again) as a prime factor, then work with the quotient, 5. </span>
<span>Is 5 divisible by 3? No, so try a bigger divisor. </span>
Is 5 divisible by 4? No, so try a bigger divisor (actually, we know it can't be divisible by 4 becase it's not divisible by 2)
<span>Is 5 divisible by 5? Yes, so write "5" as a prime factor, then work with the quotient, 1 </span>
<span>Once you end up with a quotient of "1" you're done. </span>
<span>In this case, you should have written down, "2 * 2 * 3 * 3 * 5"</span>
Answer:
Here
Step-by-step explanation:
Just pick numbers and substitute it into the equation for x
Step-by-step explanation:
16. Length of a line = sqaureroot of ((x1-x0)^2 - (y1- y0)^2)
C (2,-3) D (6,3)
CD = sqaureroot of ((6-2)^2 + (3-(-3))^2)
CD = sqaureroot of ( 16 + 36)
CD = sqaureroot of 52 = 2 root 13 = length
17. E (5, - 1) because the point is under the x axis.
Midpoint = ((x1+ x0)/2 , (y1 +y0) /2)
B (8,1) C (2, - 3)
Midpoint of BC = ((2+8)/2 , (-3+1)/2)
= (10/2 , - 2/2)
= (5, - 1)
18. Length of AE
A (4,5) E(5,-1)
Square root of ((5-4)^2 + (-1-5)^2)
Square root of (1^2 + - 6^2)
Square root of ( 1 + 36)
Square root of 37 = root 37
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