<u>Answer:</u>
Chipmunk's average acceleration during the 2.07 s time interval = 0.1256 
<u>Explanation:</u>
We have equation of motion, v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.
In this case we need to find acceleration value, we have initial velocity = 1.47 m/s, final velocity = 1.73 m/s and time taken = 2.07 seconds.
Substituting
1.73 = 1.47 + a * 2.07
a = 0.1256
Chipmunk's average acceleration during the 2.07 s time interval = 0.1256
To solve this problem we will apply the concepts related to the relationship between the voltage, the electric field and the distance, once the voltage is found we will use the definition of power, which is defined as the square of the voltage over the resistance. This is,
E = Electric field
d= Distance between the points
Replacing,
Now applying the relation for power we have,
Here
V = Voltage
R = Resistance
Replacing,
Therefore the total power emmited by the transmitter is 224509.3 W
Answer:
Explanation:
As we know that average power is the ratio of total work done and total time interval
so we will have
now we know that
so we will have
now power is given as
Kinetic, as inertia means to remain unchanged.
