Question

A helicopter, starting from rest, accelerates straight up from the roof of a hospital. The lifting force does work in raising the helicopter. An 700-kg helicopter rises from rest to a speed of 11.0 m/s in a time of 3.0 s. During this time it climbs to a height of 9.6 m. What is the average power generated by the lifting force?

Answer 1

Answer:

$P = 36068.7 Watt$

Explanation:

As we know that average power is the ratio of total work done and total time interval

so we will have

$Power = \frac{Total \: Work}{time}$

now we know that

$Work = \frac{1}{2}mv^2 + mgh$

$W = \frac{1}{2}(700)(11^2) + 700(9.8)(9.6)$

so we will have

$W = 42350 J + 68856 J$

$W = 108206 J$

now power is given as

$P = \frac{108206}{3}$

$P = 36068.7 Watt$