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Alenkasestr [34]
2 years ago
5

Find the 10th term of the geometric sequence whose common ratio is 3/2 and whose first term is 8​

Mathematics
1 answer:
igor_vitrenko [27]2 years ago
3 0

Answer: 19683/64

Step-by-step explanation:

a_{n}=8\left(\frac{3}{2} \right)^{n-1}\\\\\implies a_{10}=8 \left(\frac{3}{2} \right)^{10-1}=\boxed{\frac{19683}{64}}

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