Find the 10th term of the geometric sequence whose common ratio is 3/2 and whose first term is 8
1 answer:
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Answer:
<em> The value of [g ◦ f](x) = </em>
Step-by-step explanation:
If f(x) = 2x - 1
g(x) =
we need to find the value of [g ◦ f](x).
which means that g(f(x))
g(f(x)) =
g(f(x)) =
g(f(x)) =
<em> The value of [g ◦ f](x) = </em>
So lets set up what our question looks like.
÷ 42
So we can follow the rules of PEMDAS
and it says to figure out exponents first.
So
And..
Now we have to multiply those two numbers next...
1,160,290,625 x 1,000,000,000 = 1,160,290,625,000,000,000
Big numbers...
Now to divide that by 42
1,160,290,625,000,000,000 ÷ 42 = 27,625,967,260,000,000
I'm not sure if this is the correct answer anymore.
But my answer is 27,625,967,260,000,000
GOOD LUCK! :P
So we can follow the rules of PEMDAS
and it says to figure out exponents first.
So
And..
Now we have to multiply those two numbers next...
1,160,290,625 x 1,000,000,000 = 1,160,290,625,000,000,000
Big numbers...
Now to divide that by 42
1,160,290,625,000,000,000 ÷ 42 = 27,625,967,260,000,000
I'm not sure if this is the correct answer anymore.
But my answer is 27,625,967,260,000,000
GOOD LUCK! :P