y = 8
using the ' gradient formula' m = (y₂ - y₁)/(x₂ - x₁)
with (x₁, y₁) = (3, 3), (x₂, y₂) = (- 5, y) and m = - 
(y - 3)/( - 5 - 3) = - 
(y - 3)/(-8) = - 
multiply both sides by - 8 to eliminate fractions
y - 3 = 5
add 3 to both sides
y = 5 + 3 =8
Answer:
x= 3 1/3
Step-by-step explanation:
Answer:
he cross section becomes smaller but stays a trapezoid.
Step-by-step explanation:
Answer:
( -
, - 3)
Step-by-step explanation:
Given
19x = 15y and (x, - 3 ), that is y = - 3
Substitute y = - 3 into the equation
19x = 15(- 3) = - 45 ( divide both sides by 19 )
x = - 
Check the picture below. We know that the rectangle has a length of AB and a width of AD, so simply let's find those distances to get the perimeter and area, recall that the perimeter is simply two lengths plus two widths, and the area is just length times width.
![~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{2}~,~\stackrel{y_1}{3})\qquad B(\stackrel{x_2}{4}~,~\stackrel{y_2}{5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ AB=\sqrt{[4 - 2]^2 + [5 - 3]^2}\implies AB=\sqrt{2^2+2^2}\implies \boxed{AB=2\sqrt{2}} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=~~~~~~~~~~~~%5Ctextit%7Bdistance%20between%202%20points%7D%20%5C%5C%5C%5C%20A%28%5Cstackrel%7Bx_1%7D%7B2%7D~%2C~%5Cstackrel%7By_1%7D%7B3%7D%29%5Cqquad%20B%28%5Cstackrel%7Bx_2%7D%7B4%7D~%2C~%5Cstackrel%7By_2%7D%7B5%7D%29%5Cqquad%20%5Cqquad%20d%20%3D%20%5Csqrt%7B%28%20x_2-%20x_1%29%5E2%20%2B%20%28%20y_2-%20y_1%29%5E2%7D%20%5C%5C%5C%5C%5C%5C%20AB%3D%5Csqrt%7B%5B4%20-%202%5D%5E2%20%2B%20%5B5%20-%203%5D%5E2%7D%5Cimplies%20AB%3D%5Csqrt%7B2%5E2%2B2%5E2%7D%5Cimplies%20%5Cboxed%7BAB%3D2%5Csqrt%7B2%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{2}~,~\stackrel{y_1}{3})\qquad D(\stackrel{x_2}{3}~,~\stackrel{y_2}{2}) ~\hfill AD=\sqrt{[3 - 2]^2 + [2 - 3]^2} \\\\\\ AD = \sqrt{1^2+(-1)^2}\implies \boxed{AD=\sqrt{2}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\large Perimeter}}{2\sqrt{2}+2\sqrt{2}+\sqrt{2}+\sqrt{2}}\implies 6\sqrt{2} \\\\\\ \stackrel{\textit{\large Area}}{2\sqrt{2}\cdot \sqrt{2}\implies 2\sqrt{2^2}}\implies 4](https://tex.z-dn.net/?f=~~~~~~~~~~~~%5Ctextit%7Bdistance%20between%202%20points%7D%20%5C%5C%5C%5C%20A%28%5Cstackrel%7Bx_1%7D%7B2%7D~%2C~%5Cstackrel%7By_1%7D%7B3%7D%29%5Cqquad%20D%28%5Cstackrel%7Bx_2%7D%7B3%7D~%2C~%5Cstackrel%7By_2%7D%7B2%7D%29%20~%5Chfill%20AD%3D%5Csqrt%7B%5B3%20-%202%5D%5E2%20%2B%20%5B2%20-%203%5D%5E2%7D%20%5C%5C%5C%5C%5C%5C%20AD%20%3D%20%5Csqrt%7B1%5E2%2B%28-1%29%5E2%7D%5Cimplies%20%5Cboxed%7BAD%3D%5Csqrt%7B2%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7B%5Clarge%20Perimeter%7D%7D%7B2%5Csqrt%7B2%7D%2B2%5Csqrt%7B2%7D%2B%5Csqrt%7B2%7D%2B%5Csqrt%7B2%7D%7D%5Cimplies%206%5Csqrt%7B2%7D%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7B%5Clarge%20Area%7D%7D%7B2%5Csqrt%7B2%7D%5Ccdot%20%5Csqrt%7B2%7D%5Cimplies%202%5Csqrt%7B2%5E2%7D%7D%5Cimplies%204)