Answer:
The angle between [A_F] and the base of the cone = 68.2°
The area of the base of the cone ≈ 12.57 m²
Step-by-step explanation:
The given parameters are;
The height of the cone = 5 m
The base radius of the cone = 2 m
The angle which the A
C = 120°
Therefore, we have;
The angle between [A_F] and the base of the cone = The angle between [CF] and the base of the cone
The angle between [CF] and the base of the cone = tan⁻¹(5/2) = tan⁻¹(2.5) ≈ 68.2°
∴ The angle between [A_F] and the base of the cone = The angle between [CF] and the base of the cone = 68.2°
The angle between [A_F] and the base of the cone = 68.2°
The area of the base of the cone = π × r² = π × 2² = 4·π ≈ 12.57
The area of the base of the cone ≈ 12.57 m².
78,000 rounded to the nearest ten thousand is 80,000.
Answer:
42
Step-by-step explanation:
11 - 4 = 7
49 - 7 = 42
Answer:
ok so if equilateral triangle has 1 inch and box has 9 inch of height, the lateral area would be 27 square-inch
Step-by-step explanation:
Answer:
x= 70
Step-by-step explanation:
In this question you have to use BODMAS. This indicates that you have to do the equation in the brackets first. Therefore, 3x15= 45. Then you add 25, which will give you 70.