In a standard shuffled deck of 52 cards, half of the cards are black and half of the cards are red: (26 black cards, 26 red cards).
Since we are interested in pulling a black card first, the probability is 26/52.
Without replacing the card we have chosen, we are left with 51 total cards in the entire deck (25 black cards, 26 red cards).
Now that we want to pull a red card, we know that the probability will be 26/51.
Since we are interested in both events occurring simultaneously, we must multiply the probability of the first by the probability of the second, aka: (26/52) * (26/51)
The answer we are given is 0.2549
Answer:
Step-by-step explanation:it’s 3 thank me
The correct answer here would be D. -1(3x+1)(x+5). You can find this answer by redistributing the problem.
-1(3x+1)(x+5)
-1(3x²+15x+1x+5)
-1(3x²+16x+5)
-3x²-16x-5
Using the math above, we can see that when we redistribute we get the original equation. That makes Choice D correct.
2(
x + 4) = 
x + 4 which is the second option is the equivalent expression.
Explanation:
First, we need to calculate the value of two-fifths of x. It means 2 portions out of the five portions of x which equates to x.
Now we calculate the values of the two expresssions on the LHS.
1) 2 (two-fifths x + 2) = 2 (x + 2) = x + 4.
2) (two-fifths x + 4) = 2(x + 4) = x + 8.
Now we determine values of the four expressions on the RHS.
1) Two and two-fifths x + 1 = 2x + 1
2) Four-fifths x + 4 = x + 4
3) Four-fifths x + 2 = x + 2
4) Two and two-fifths x + 8 = 2x + 8.
Out of the various LHS and RHS values, the 
LHS value and 
RHS value is the same. So option 2 is the answer.
