Answer:
x = -1 and y = -1
Step-by-step explanation:
Solve 3x+3y=−6;−x+y=0
Steps:
I will solve your system by substitution.
−x+y=0;3x+3y=−6
Step: Solve−x+y=0for y:
−x+y+x=0+x(Add x to both sides)
y=x
Step: Substitutexforyin3x+3y=−6:
3x+3y=−6
3x+3x=−6
6x=−6(Simplify both sides of the equation)
6x
6
=
−6
6
(Divide both sides by 6)
x=−1
Step: Substitute−1forxiny=x:
y=x
y=−1
Answer:
x=−1 and y=−1
Answer:
There are 165 ways to distribute the blackboards between the schools. If at least 1 blackboard goes to each school, then we only have 35 ways.
Step-by-step explanation:
Essentially, this is a problem of balls and sticks. The 8 identical blackboards can be represented as 8 balls, and you assign them to each school by using 3 sticks. Basically each school receives an amount of blackboards equivalent to the amount of balls between 2 sticks: The first school gets all the balls before the first stick, the second school gets all the balls between stick 1 and stick 2, the third school gets the balls between sticks 2 and 3 and the last school gets all remaining balls.
The problem reduces to take 11 consecutive spots which we will use to localize the balls and the sticks and select 3 places to put the sticks. The amount of ways to do this is
As a result, we have 165 ways to distribute the blackboards.
If each school needs at least 1 blackboard you can give 1 blackbooard to each of them first and distribute the remaining 4 the same way we did before. This time there will be 4 balls and 3 sticks, so we have to put 3 sticks in 7 spaces (if a school takes what it is between 2 sticks that doesnt have balls between, then that school only gets the first blackboard we assigned to it previously). The amount of ways to localize the sticks is
. Thus, there are only 35 ways to distribute the blackboards in this case.
Step-by-step explanation:
Slope (m) =ΔYΔX=12=0.5θ =arctan(ΔY)ΔX=26.565051177078°ΔX = 6 – 4 = 2ΔY = 10 – 9 = 1Distance (d) = √ΔX2 + ΔY2 = √5
= 2.2360679774998
Your answer would be <em><u>2*10^2 + 1*10^1 + 5*1^1</u></em>