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3 years ago

This is part of my knowledge check that's due today at 11:59 am. Please help me on this question

Mathematics

1 answer:

lys-0071 [83]3 years ago

6 0

7 cm (you divide 56 by 8)

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How do you ordered pair that represents a solutions to the system of linear inequalities below?

ELEN [110]

Answer:

x=No (Minimum)

Step-by-step explanation:

Hope this helps

4 0

2 years ago

use Taylor's Theorem with integral remainder and the mean-value theorem for integrals to deduce Taylor's Theorem with lagrange r

Vadim26 [7]

Answer:

As consequence of the Taylor theorem with integral remainder we have that

$f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \cdots + \frac{f^{(n)}(a)}{n!}(x-a)^n + \int^a_x f^{(n+1)}(t)\frac{(x-t)^n}{n!}dt$

If we ask that $f$ has continuous $(n+1)$ th derivative we can apply the mean value theorem for integrals. Then, there exists $c$ between $a$ and $x$ such that

$\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}dt = \frac{f^{(n+1)}(c)}{n!} \int^a_x (x-t)^n d t = \frac{f^{(n+1)}(c)}{n!} \frac{(x-t)^{n+1}}{n+1}\Big|_a^x$

Hence,

$\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}d t = \frac{f^{(n+1)}(c)}{n!} \frac{(x-t)^{(n+1)}}{n+1} = \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1} .$

Thus,

$\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}d t = \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1}$

and the Taylor theorem with Lagrange remainder is

$f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \cdots + \frac{f^{(n)}(a)}{n!}(x-a)^n + \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1}$ .

Step-by-step explanation:

5 0

3 years ago

Identify the following number as rational or irrational 3.2573820193748...

Bingel [31]

Answer: Irrational

Step-by-step explanation:

4 0

2 years ago

Perform the operation. Enter your answer in scientific notation. 9 × 102 − 5.6 × 102 =

Arada [10]

Answer:

1489.2

Step-by-step explanation:

9*102-5.6*102=

102(9+5.6) =

102(9.0+5.6) =

102(14.6) =

102*14.6=

14.6*(100+2) =

(14.6*100+14.6*2) =

(1460+(14+.6) *2) =

1460+(28+1.2) =

1460+(28.0+1.2) =

1460+29.2=

1460.0+

29.2

=1489.2

3 0

3 years ago

Read 2 more answers

Plssss help due today

asambeis [7]

160-80 = 80

80/2 = 40

angle BCD = 40 degrees

please mark brainliest

6 0

3 years ago