Answer:
Reactive power is 1.152 VARs
Step-by-step explanation:
We are given that in a parallel circuit,
,R=47kΩ and 
=50kΩ.
reactive power means the dissipating power resulting from inductive and capacitive loads measured in volt-amperes reactive(VAR).Since our circuit has inductor only, reactive power will be power dissipated from inductor.
Current through inductor=
milli amps=0.0048 A
Reactive power = (current flowing through inductor)X (Voltage across inductor)
Hence reactive power = 0.0048 X 240=1.152 VARs
You said that Y = Mx + B
Subtract B from each side: Y - B = Mx
Divide each side by 'x' : (Y - B) / x = M
Answer:
x = -30
y = -20
Step-by-step explanation:
x - 12y = 210..... (I)
x - 6y = 90..... (II)
Subtract equation (II) from (I)
- 12y - (-6y) = 210 - 90
-12y + 6y = 120
-6y = 120
Divide through by -6y
Therefore, y = -20
Substitute y = -20 in equation (II)
x -6 (-20) = 90
x + 120 = 90
x = 90 - 120
x = -30
Hope that helped
Answer:
<h2>The GCF of 18, 36 and 45 is 9.</h2>
The answer is 0.82 so he eat 82 percent of the candy bar
