Answer:
a) 0.2778
b) 0.3611
c) 0.1389
d) 0.0833
Step-by-step explanation:
We have a total of 5 + 3 + 1 = 9 balls
a) First ball being yellow: we have 5 yellow balls, so P1 = 5/9
Second ball being yellow after one yellow was drawn: we have 4 yellows and 8 balls, so P2 = 4/8 = 1/2
Both yellows: P = P1 * P2 = 5/18 = 0.2778
b) Both blues:
P1 = 3/9 = 1/3
P2 = 2/8 = 1/4
P = P1 * P2 = 1/12 = 0.0833
Both yellows or both blues: 5/18 + 1/12 = 0.2778 + 0.0833 = 0.3611
c) First yellow: P1 = 5/9
Second red: P2 = 1/8
Pa = P1 * P2 = 5/72
or
First red: P3 = 1/9
Second yellow: P4 = 5/8
Pb = P3 * P4 = 5/72
P = Pa + Pb = 10/72 = 5/36 = 0.1389
d) First blue: P1 = 3/9 = 1/3
Second red: P2 = 1/8
Pa = P1 * P2 = 1/24
or
First red: P3 = 1/9
Second blue: P4 = 3/8
Pb = P3 * P4 = 1/24
P = Pa + Pb = 2/24 = 1/12 = 0.0833
Fill your inequality in with the y and x provided and then do the math. (4, -1) would fill in like this (I will use brackets to indicate absolute value symbols, since there are none in the equation editor):
![-1\ \textgreater \ [4]-5](https://tex.z-dn.net/?f=-1%5C%20%5Ctextgreater%20%5C%20%5B4%5D-5)
The right side is in fact equal to the left side so that's not the answer. For (-1, -4):
![-4\ \textgreater \ [-1]-5](https://tex.z-dn.net/?f=-4%5C%20%5Ctextgreater%20%5C%20%5B-1%5D-5)
and these are also equal. Let's try C now (-4, 1):
![1\ \textgreater \ [-4]-5](https://tex.z-dn.net/?f=1%5C%20%5Ctextgreater%20%5C%20%5B-4%5D-5)
. The absolute vale of -4 is 4 so 4 - 5 = -1 which is, in fact, less than 1. So C is our answer.
Answer:
The margin of error will be "0.65". A further explanation is provided below.
Step-by-step explanation:
The given values are:
n = 343
x = 110
At 99% confidence level,
%


then,


or,


Now,
The point estimate will be:
⇒ 
⇒ 
⇒ 
or,
⇒ 
⇒
The margin of error will be:
⇒ 
On substituting the above values, we get
⇒ 
⇒ 
⇒ 
hence,
⇒ 
⇒ 
⇒ 
Answer:
The conclusion is that the robber is fast.
Step-by-step explanation:
The first assertion is that if the robber is fast, the police can't catch him. The next information that you get is that they indeed <em>can't </em>catch him, showing that this is the answer.