Answer:
x = 125
Step-by-step explanation:
Given
= 25
Multiply both sides by 5 to clear the fraction
x = 5 × 25 = 125
x = 125
First we are going to group the terms that contains the common factor

in one parenthesis, and the other ones in another parenthesis:


Notice that our the terms in our first parenthesis have a common factor

, and the terms in our second one have the common factor

. Lets factor those out:

Now we have a common factor

in both terms, so we can factor those out as well:

We can conclude that the completely factored expression ordered alphabetically is

.
Answer:

Step-by-step explanation:
Start by factoring out a -1...

Now, we have to find two integers that multiply to get -16 and have a sum of 6:
(-2)*8=-16
-2+8=8-2=6
Using this, we can split 6x into -2x and 8x...

Factor the first and second half separately...
![f(x)=-[(x^2-2x)+(8x-16)]\\f(x)=-[x(x-2)+8(x-2)]\\](https://tex.z-dn.net/?f=f%28x%29%3D-%5B%28x%5E2-2x%29%2B%288x-16%29%5D%5C%5Cf%28x%29%3D-%5Bx%28x-2%29%2B8%28x-2%29%5D%5C%5C)
Since both x and 8 are being multiplied by x-2, we can combine them to get...

Answer:
If X repeats and y does not it is not an example of a function. But if the y repeats and has two different x values that can be known as a function.
For an example ( 1 , 3) and (1, 4) thats not an example of a function because the x value is repeating but if its ( 1, 4) and (2,4) a thats
a function because no x value is repeating the x value is known as an independent value. Does that make sense?
"This relation is definitely a function because every x-value is unique and is associated with only one value of y. So for a quick summary, if you see any duplicates or repetitions in the x-values, the relation is not a function."