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IgorLugansk [536]
3 years ago
14

Find an equation of a line that is parallel to y = 5x + 9 and passes through the point (3, 11).

Mathematics
1 answer:
sattari [20]3 years ago
6 0

Answer:

y = 5x - 4

Step-by-step explanation:

The equation y = 5x + 9 currently does not pass through the point (3, 11). It asks us to create the equation of a line parallel to y = 5x + 9. So all we have to change is the 9, where the line passes through the y-coordinate. The slope, 5x, has to stay the same, otherwise, the new line will not be parallel to  y = 5x + 9.

The line has to pass through to point (3, 11). The 3, stands for the x value, and 11 the y value. If we start at the y value of -4, that means the very next point would be (1, 1), and the next one, (2, 6), and the final one, (3, 11). This is because we know the slope of the line is 5x, that means for every 1 gained x value, the y value gains 5 values.

So, the equation of the new line would be this:

y = 5x - 4

I Hope That This Helps! :)

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»»————- ★ ————-««

I believe your answer is:  

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»»————- ★ ————-««  

Here’s why:  

⸻⸻⸻⸻

\boxed{\text{Evaluating the function...}}\\\\g(x)=-4x+4; g(3)\\\\--------------\\\rightarrow g(3)=-4(3)+4\\\\\rightarrow g(3) = -12  + 4\\\\\rightarrow \boxed{g(3)=-8}

⸻⸻⸻⸻

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

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