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xxTIMURxx [149]
3 years ago
7

How can you solve problems involving equations that contain adding subtracting multiplication or division

Mathematics
1 answer:
kiruha [24]3 years ago
8 0
Use PEMDAS.
Compute in order of parentheses, exponents, multiplication, division, addition, subtraction.
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Which of the following is true about a nonlinear function?
Mila [183]
It is not straight and does not always pass through 0,0
so A, C, and D are incorrect.

Look up nonlinear function, and it shows a curved line.

The answer is B. It can be curved.
8 0
3 years ago
Read 2 more answers
9: Part A The diameter of a circle is 63 centimeters. ​Find its circumference. ​Use π=3.14. ​ A 31.5 centimeters B 98.91 centime
BaLLatris [955]
Part A:
The circumference of the circle is 197.92.

Explanation:
The formula for circumference of a circle is C=2 πr. If you insert the numbers, it would be C=2 x 3.14 x 31.5. Hence, the answer is 197.92.

Part B:
The area is 3117.25 square cm.

Explanation:
The formula for area of a circle is A= πr ². Inserting the numbers, it is A=3.14 x 31.5 ². Therefore the answer is 3117.25 cm ².
6 0
3 years ago
Find the perimeter of ABCD<br> Find the area of Area
san4es73 [151]

Step-by-step explanation:

A = (1, 3)

B = (3, 6)

C = (9, 2)

D = (7, -1)

the distance between 2 points is given by the Pythagoras equation based on the coordinate differences as legs of virtual right-angled triangles.

AD for example we get from

AD² = (7-1)² + (-1 - 3)² = 6² + (-4)² = 36 + 16 = 52

AD = sqrt(52) = sqrt(4×13) = 2×sqrt(13)

and AB we get from

AB² = (3-1)² + (6-3)² = 2² + 3² = 4 + 9 = 13

AB = sqrt(13)

the perimeter of the given rectangle is

2×sqrt(52) + 2×sqrt(13) = 2×2×sqrt(13) + 2×sqrt(13) =

= 6×sqrt(13) = 21.63330765...

and the area of the rectangle is

2×sqrt(13)×sqrt(13) = 2×13 = 26

7 0
2 years ago
The histogram displays different numbers of days that customers rented a car. Which interval represents the most common number o
sleet_krkn [62]

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete, as the histogram is not attached.

However, the solution to your question is to select the interval with the highest frequency

Take for instance, after getting readings from the histogram, yiu have:

1 - 10: 8

11 - 20: 5

21 - 30: 11

31 - 40: 2

And so on.......

Interval 11 - 20 will represent the required interval because it has the highest frequency.

3 0
3 years ago
Will mark Brainlest help plsssss​
r-ruslan [8.4K]

Answer:

45 is answer I guess cuz my teacher taught me just like that

7 0
3 years ago
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