Which of the expressions are equivalent to the one below? Check all that
1 answer:
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Given:
The largest circle has a radius of R=7 units.
Let x be the radius of the large shaded circle.
The small shaded circles have a radius of 1/5 of the large shaded circle.
=> the small shaded circles have a radius of r=x/5
By adding up radii, we have the equation
2(r+x+r)=2(x/5+x+x/5)=2R=2*7=14
Simplify:
7x/5=14/2
x=5
=> r=1
Area of outer circle =
Area of large shaded circle =
Area of 4 small shaded circles =
Total area of shaded circles =
Shaded area as a fraction of that of the outer circle
The largest circle has a radius of R=7 units.
Let x be the radius of the large shaded circle.
The small shaded circles have a radius of 1/5 of the large shaded circle.
=> the small shaded circles have a radius of r=x/5
By adding up radii, we have the equation
2(r+x+r)=2(x/5+x+x/5)=2R=2*7=14
Simplify:
7x/5=14/2
x=5
=> r=1
Area of outer circle =
Area of large shaded circle =
Area of 4 small shaded circles =
Total area of shaded circles =
Shaded area as a fraction of that of the outer circle
Answer:
32,292,000
Step-by-step explanation:
In your question, it asks how many license plate combinations we could make WITHOUT repeats.
We need some prior knowledge to answer this question.
We know that:
- There are 26 letters in the alphabet
- We can make 10 digits (0 - 9)
With the information we know above, we can solve the question.
Since we CAN'T have repeats, we would be excluding a letter or number for each license plate.
We're going to need to multiply each "section" in order to find how many combinations of license plates we can make.
We decrease by one letter and one number in each section since we can't have repeats.
Now, we can solve.
Work:
When you're done multiplying, you should get 32,292,000.
This means that there could be 32,292,000 different combinations of license plates.
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