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bagirrra123 [75]
3 years ago
7

Vertex A in quadrilateral ABCD lies at (-3, 2). If you rotate ABCD 180° clockwise about the origin, what will be the coordinates

of A′ of the rotated quadrilateral A′B′C′D′?
Mathematics
1 answer:
natali 33 [55]3 years ago
4 0

The rule for a rotation by 180° about the origin is (x,y) -->(−x,−y)

So A(-3, 2) to A'(3, -2)

Answer:

A'(3, -2)

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Please explain the problem attached
borishaifa [10]
<h3>Answer:</h3>

F (3x, 3y)

<h3>Explanation:</h3>

Dilation about the origin multiplies each coordinate by the dilation factor. For some coordinates (x, y), dilation by a factor of 3 means the new coordinates are ...

... 3×(x, y) = (3x, 3y)

_____

<em>Comment on the problem</em>

The way the problem is worded, you expect an answer choice that will be specific to the coordinates of point A. There are none.

Instead, the answer choices are generic, corresponding to dilation of a point (x, y) by a factor of 3, translation up and to the right by 3, dilation by a factor of 1/3, and translation down and to the left by 3.

8 0
4 years ago
Solve the following inequality: -20 &lt; 4 - 2x<br> A. 8 &gt;x<br> B. 8 C. 12 &gt; x<br> D. 12
Mama L [17]

Answer:

-20 < 4 - 2x (subtract 4 from both sides)

-24 < -2x (divide each side by -2)

12> x  (when you divide by a negative number, the inequality flips)

x< 12 ( I always put it so x is first)

so the answer is C

6 0
3 years ago
High expression is equivalent to ^4 square root x^10
Talja [164]

In order to find which <u>expression</u> is <u>equivalent</u> to \sqrt[4]{x^{10}}, <u>simplify</u> all given expressions:

0.

\sqrt[4]{x^{10}}=x^{\frac{10}{4}}=x^{\frac{5}{2}}=x^{2.5}.

1.

x^2(\sqrt[4]{x^2})=x^2\cdot x^{\frac{2}{4}}=x^2\cdot x^{\frac{1}{2}}=x^2\cdot x^{0.5}=x^{2.5}.

2.

x^{2.2}.

3.

x^3(\sqrt[4]{x} )=x^3\cdot x^{\frac{1}{4}}=x^3\cdot x^{0.25}=x^{3.25}.

4.

x^5.

Therefore,

Answer: correct choice is A

7 0
4 years ago
Let Q(x, y) be the predicate "If x &lt; y then x2 &lt; y2," with domain for both x and y being R, the set of all real numbers.
Levart [38]

Answer:

a) Q(-2,1) is false

b) Q(-5,2) is false

c)Q(3,8) is true

d)Q(9,10) is true

Step-by-step explanation:

Given data is Q(x,y) is predicate that x then x^{2}. where x,y are rational numbers.

a)

when x=-2, y=1

Here -2 that is x  satisfied. Then

(-2)^{2}

4 this is wrong. since 4>1

That is x^{2}>y^{2} Thus Q(x,y) =Q(-2,1)is false.

b)

Assume Q(x,y)=Q(-5,2).

That is x=-5, y=2

Here -5 that is x this condition is satisfied.

Then

(-5)^{2}

25 this is not true. since 25>4.

This is similar to the truth value of part (a).

Since in both x satisfied and x^{2} >y^{2} for both the points.

c)

if Q(x,y)=Q(3,8) that is x=3 and y=8

Here 3 this satisfies the condition x.

Then 3^{2}

9 This also satisfies the condition x^{2}.

Hence Q(3,8) exists and it is true.

d)

Assume Q(x,y)=Q(9,10)

Here 9 satisfies the condition x

Then 9^{2}

81 satisfies the condition x^{2}.

Thus, Q(9,10) point exists and it is true. This satisfies the same values as in part (c)

6 0
3 years ago
I u asnwer this u are gay
Alborosie

Answer:

well I mean I already am gay well I'm really lesbian so take that!

6 0
3 years ago
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