An animal cell lacking carbohydrates on the external surface of its plasma membrane would likely be impaired in CELL TO CELL RECOGNITION.
Carbohydrates have diverse functions, one of their functions is that they serve as a recognition signal at the surface of cells.
Carbohydrates located on the surface of cells enable cells to recognize and communicate with one another.
Estuaries, often reffered to as the nurseries of the sea provide feedind habitats for many aquatic animals and plants. Fish and shellfish commonly eaten in the U.S such as oyesters and Salmon complete almost half of their lifecycles in estuaries. Due to its shallow water,Pamlico estuary especially provides opportunities such as Fishing, crabbing and watersports as well.
We can be able to determine this concept by basing our facts on two concepts. Nutrient Influx, upon reaching the estuarian ecosystem, the nutrients in the presence of sunlight undergoes photosynthesis and produce phytoplanktons. Basically, where there is sunlight, we can assume there is a nutrient influx. Presence of Phytoplanktons will in turn help attract animals such as fish. Also, another contribution of nutrient influx is manure produced by the animals
Sewage treatment plans and fertilizer runoff. Auto emissions of nitrogen, fertilizers applied on golf courses and home gardens can contribute. Some plankton species may produce toxins that might cause these outbreaks
Answer:
<em><u>Solar Cell for Transportation.</u></em>
<em><u>Solar Cell for Transportation.Solar Cells in Calculators.</u></em>
<em><u>Solar Cell for Transportation.Solar Cells in Calculators.Solar Cell Panels. </u></em>
Explanation:
hope this helps you!!
I think it would either be c or d...
Answer:
1500
Explanation:
Let's assume that the allele for yellow seed color is "Y" and the allele for green seed color is "y". Genotype of pure breeding yellow seeded plant would be "YY" and that of the green seeded plant would be "yy". A cross between YY and yy gives all heterozygous yellow seeded plants (Yy) in F1 progeny. Self pollination of two F1 plants (Yy x Yy) obtains F2 generation in 3 yellow: 1 green ratio.
The total population size of F2 generation = 2000
The proportion of yellow seeded plants in F2 generation = 3/4 (since the F2 phenotype ratio is given 3 yellow: 1 green)
Therefore, total number of yellow seeded plants in F2 progeny = 3/4 x 2000= 1500
