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nikklg [1K]
3 years ago
13

Four more than twice a number si 24. Write the equation in Numbers

Mathematics
1 answer:
kvv77 [185]3 years ago
6 0

Answer:

4+2x=24

Step-by-step explanation:

4 more = 4+

twice a number = 2x (multiply the input by two)

is 24 = =24 (after inputing the right number into "x" it should equal 24.

Hoped this helped

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Plzzz help! will give branliest if you can do this one!!! i also need help with other math problems
kotykmax [81]
I believe it’s the last answer. Rotation of 180 degrees clockwise with a dilation of 5.
4 0
3 years ago
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When two six-sided dice are rolled, there are 36 possible outcomes. Find the probability that the sum is not 5.
zaharov [31]

Answer:

p(Not\ 5) = \frac{8}{9}

Step-by-step explanation:

Given:

Txo six-sided dice are rolled.

Total number of outcomes n(S) = 36

We need to find the probability that the sum is not equal to 5 p(Not 5).

Solution:

Using probability formula.

P(E)=\frac{n(E)}{n(S)}  ----------------(1)

Where:

n(E) is the number of outcomes favourable to E.

n(S) is the total number of equally likely outcomes.

The sum of two six-sided dice roll outcome is equal to 5 as.

Outcome as 5: {(1,4), (2,3), (3,2), (4,1)}

So, the total favourable events n(E) = 4

Now, we substitute n(E) and n(s) in equation 1.

P(5)=\frac{4}{36}

p(5) = \frac{1}{9}

Using formula.

p(Not\ E) + p(E) = 1

p(Not\ 5) + p(5) = 1

Now we substitute p(5) in above equation.

p(Not\ 5) + \frac{1}{9} = 1

p(Not\ 5) = 1-\frac{1}{9}

p(Not\ 5) = \frac{9-1}{9}

p(Not\ 5) = \frac{8}{9}

Therefore, the sum of two six-sided dice roll outcome is not equal to 5.

p(Not\ 5) = \frac{8}{9}

6 0
3 years ago
Help me fjfjsncjdhdhfh​
Deffense [45]

Step-by-step explanation:

=>  2 {x}^{2}  +  \frac{7}{2}x +  \frac{3}{4}  = 0

=> \frac{8 {x}^{2}  + 14x + 3}{4} = 0

=> 8 {x}^{2}  + 14x + 3 = 0

=> 8 {x}^{2}  + 12x + 2x + 3 = 0

=> 4x(2x + 3) + 1(2x + 3) = 0

= > (2x + 3)(4x + 1) = 0

=  > x =  -  \frac{3}{2} or \frac{ - 1}{4}

option C

8 0
3 years ago
PLZ HELP! <br> Question Down Below!
Tresset [83]
Well it depends on where the number is at. So you have to estimate to the closest number on the answers. Ok?
6 0
3 years ago
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Line a and b are perpendicular lines.If line a is represented by y=s/t x+10 and line b is represented by y=q/r -4 where s,t,q an
alekssr [168]

Answer:

The options are not shown, so i will answer in a general way.

First, for a line of the form:

y = a*x + b

All the perpendicular lines will have a slope of -(1/a), then we can write a general perpendicular line as:

y = -(1/a)*x + c.

In this problem we have the perpendicular lines:

y=(s/t)*x+10

y = (q/r)*x - 4

Because those lines are perpendicular, we must have that:

(q/r) = -(1/(s/t)) = -(t/s)

q/r = -t/s

and we knew that s, t, q and r are integers (where t and r can not be equal to zero), and because of this relation, where we can see that in the denominator at the right we have the integer s, we can conclude that s can not be zero (we can not divide by zero).

And we know that t and s are both different than zero, then:

-t/s ≠ 0.

This means that:

q/r ≠ 0

And from this, we can conclude that q is different than zero.

7 0
3 years ago
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