Answer:
75 each month
Step-by-step explanation:
578-128=450
450/6=75
![\huge \boxed{\mathbb{QUESTION} \downarrow}](https://tex.z-dn.net/?f=%20%5Chuge%20%5Cboxed%7B%5Cmathbb%7BQUESTION%7D%20%5Cdownarrow%7D)
- How do you simplify this?
- x²y+xy² / y²+2/5 × xy
![\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}](https://tex.z-dn.net/?f=%20%5Clarge%20%5Cboxed%7B%5Cmathbb%7BANSWER%5C%3A%20WITH%5C%3A%20EXPLANATION%7D%20%5Cdownarrow%7D)
![\sf\frac{ { x }^{ 2 } y+x { y }^{ 2 } }{ { y }^{ 2 } + \frac{ 2 }{ 5 } \times xy } \\](https://tex.z-dn.net/?f=%20%5Csf%5Cfrac%7B%20%20%7B%20x%20%20%7D%5E%7B%202%20%20%7D%20%20y%2Bx%20%7B%20y%20%20%7D%5E%7B%202%20%20%7D%20%20%20%20%7D%7B%20%20%7B%20y%20%20%7D%5E%7B%202%20%20%7D%20%20%2B%20%5Cfrac%7B%202%20%20%7D%7B%205%20%20%7D%20%20%20%5Ctimes%20%20xy%20%20%7D%20%5C%5C%20)
Factor the expressions that are not already factored.
_____
<u>How </u><u>to</u><u> factorise</u><u> </u><u>:</u><u>-</u>
<u>NUMERATOR</u> ![\downarrow](https://tex.z-dn.net/?f=%5Cdownarrow)
![\sf \: x ^ { 2 } y + x y ^ { 2 }](https://tex.z-dn.net/?f=%20%5Csf%20%5C%3A%20x%20%5E%20%7B%202%20%7D%20y%20%2B%20x%20y%20%5E%20%7B%202%20%7D)
Factor out xy.
![\sf \: xy\left(x+y\right)](https://tex.z-dn.net/?f=%20%5Csf%20%5C%3A%20xy%5Cleft%28x%2By%5Cright%29%20)
<u>DENOMINATOR</u> ![\downarrow](https://tex.z-dn.net/?f=%5Cdownarrow)
![\sf{ y }^{ 2 } + \frac{ 2 }{ 5 } \times xy \\](https://tex.z-dn.net/?f=%20%5Csf%7B%20y%20%20%7D%5E%7B%202%20%20%7D%20%20%2B%20%5Cfrac%7B%202%20%20%7D%7B%205%20%20%7D%20%20%20%5Ctimes%20%20xy%20%5C%5C%20)
Factor out 1/5.
![\sf \: {\frac{1}{5}y\left(2x+5y\right)} \\](https://tex.z-dn.net/?f=%20%5Csf%20%5C%3A%20%7B%5Cfrac%7B1%7D%7B5%7Dy%5Cleft%282x%2B5y%5Cright%29%7D%20%20%5C%5C%20)
_____
Continuing...
![\sf\frac{xy\left(x+y\right)}{\frac{1}{5}y\left(2x+5y\right)} \\](https://tex.z-dn.net/?f=%20%5Csf%5Cfrac%7Bxy%5Cleft%28x%2By%5Cright%29%7D%7B%5Cfrac%7B1%7D%7B5%7Dy%5Cleft%282x%2B5y%5Cright%29%7D%20%20%5C%5C%20)
Cancel out y in both the numerator and denominator.
![\sf\frac{x\left(x+y\right)}{\frac{1}{5}\left(2x+5y\right)} \\](https://tex.z-dn.net/?f=%20%5Csf%5Cfrac%7Bx%5Cleft%28x%2By%5Cright%29%7D%7B%5Cfrac%7B1%7D%7B5%7D%5Cleft%282x%2B5y%5Cright%29%7D%20%20%5C%5C%20)
Expand the expression.
![\sf\frac{x^{2}+xy}{\frac{2}{5}x+y} \\](https://tex.z-dn.net/?f=%20%5Csf%5Cfrac%7Bx%5E%7B2%7D%2Bxy%7D%7B%5Cfrac%7B2%7D%7B5%7Dx%2By%7D%20%20%5C%5C%20)
This can further simplified to as ![\downarrow](https://tex.z-dn.net/?f=%5Cdownarrow)
![= \boxed{\boxed{\bf\frac{5x\left(x +y\right)}{2x+5y}}}](https://tex.z-dn.net/?f=%20%3D%20%20%20%20%5Cboxed%7B%5Cboxed%7B%5Cbf%5Cfrac%7B5x%5Cleft%28x%20%20%2By%5Cright%29%7D%7B2x%2B5y%7D%7D%7D)
Answer:
You can decide where to put the first digit because you know 153 doesn't fit into 6 or 61. But you know it can fit into 613. You put it there.
The answer is 25z if you need to know how i can show you
For example, the three 2s.
in the box show that there are 3 groups of 2 objects each.You can write the multiplication equation 3 2 = 6 to show that 3 groups of 2 equals 6 in all.You can also write the division equation 6 2 = 3 to show that 6 divided into groups of 2 equals 3 groups.