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adell [148]
3 years ago
14

One hose can fill a small swimming pool in 95 minutes. A larger hose can fill the pool in 30 minutes. How long will it take the

two hoses to fill the pool working
together?
Mathematics
2 answers:
lianna [129]3 years ago
8 0

Answer:

45 mins for two small hoses and 15 mins for two large ones

Step-by-step explanation:

Lemur [1.5K]3 years ago
3 0

Answer:

I believe this is 65 minutes. if you subtract 30 minutes from 95 you have 65

Step-by-step explanation:

You might be interested in
Which expression has a positive quotient?
svp [43]

Answer:

Only 1st option Negative three-fourths divided by Negative two-thirds has positive quotient.

Option A is correct.

Step-by-step explanation:

We will solve to find out Which expression has a positive quotient.

We know the division rule: \frac{-a}{-b}=\frac{a}{b} and \frac{-a}{b}=\frac{-a}{b}

We will use these rules

1) Negative three-fourths divided by Negative two-thirds

=\frac{-\frac{3}{4} }{-\frac{2}{3} }\\=-\frac{3}{4}\times -\frac{3}{2}\\=\frac{9}{8}

The quotient is positive.

2) Negative StartFraction 1 over 8 EndFraction divided by 3 and one-fifth

\frac{-\frac{1}{8} }{3\frac{1}{5} }\\=\frac{-\frac{1}{8} }{\frac{16}{5} }\\=-\frac{1}{18} \times \frac{5}{16}\\=-\frac{5}{288}

The quotient is negative.

3) 2 and StartFraction 2 over 7 EndFraction divided by negative one-fifth

\frac{2\frac{2}{7} }{-\frac{1}{5} }\\= \frac{\frac{16}{7} }{-\frac{1}{5} }\\=\frac{16}{7} \times -5\\=-\frac{80}{7}

The quotient is negative.

4) Negative 6 divided by Five-thirds

\frac{-6}{\frac{5}{3} }\\=-6 \times \frac{3}{5}\\=-\frac{18}{5}

The quotient is negative.

So, only 1st option Negative three-fourths divided by Negative two-thirds has positive quotient.

Option A is correct.

4 0
3 years ago
Read 2 more answers
The liquid base of an ice cream has an initial temperature of 86°C before it is placed in a freezer with a constant temperature
Karolina [17]

The temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

From Newton's law of cooling, we have that

T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}

Where

(t) = \ time

T_{(t)} = \ the \ temperature \ of \ the \ body \ at \ time \ (t)

T_{s} = Surrounding \ temperature

T_{0} = Initial \ temperature \ of \ the \ body

k = constant

From the question,

T_{0} = 86 ^{o}C

T_{s} = -20 ^{o}C

∴ T_{0} - T_{s} = 86^{o}C - -20^{o}C = 86^{o}C +20^{o}C

T_{0} - T_{s} = 106^{o} C

Therefore, the equation T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt} becomes

T_{(t)}=-20+106 e^{kt}

Also, from the question

After 1 hour, the temperature of the ice-cream base has decreased to 58°C.

That is,

At time t = 1 \ hour, T_{(t)} = 58^{o}C

Then, we can write that

T_{(1)}=58 = -20+106 e^{k(1)}

Then, we get

58 = -20+106 e^{k(1)}

Now, solve for k

First collect like terms

58 +20 = 106 e^{k}

78 =106 e^{k}

Then,

e^{k} = \frac{78}{106}

e^{k} = 0.735849

Now, take the natural log of both sides

ln(e^{k}) =ln( 0.735849)

k = -0.30673

This is the value of the constant k

Now, for the temperature of the ice cream 2 hours after it was placed in the freezer, that is, at t = 2 \ hours

From

T_{(t)}=-20+106 e^{kt}

Then

T_{(2)}=-20+106 e^{(-0.30673 \times 2)}

T_{(2)}=-20+106 e^{-0.61346}

T_{(2)}=-20+106\times 0.5414741237

T_{(2)}=-20+57.396257

T_{(2)}=37.396257 \ ^{o}C

T_{(2)} \approxeq  37.40 \ ^{o}C

Hence, the temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

Learn more here: brainly.com/question/11689670

6 0
2 years ago
Read 2 more answers
How do you do this we need some really big help so help us please
rewona [7]
Well that's division.
•36 divided by 9 is equal to 4.
• 81 divided by 9 is equal to 9.
•45 divided by 5 is equal to 9.
•56 divided by 7 is equal to 8.
•42 divided by 7 is equal to 6.
7 0
3 years ago
Solve the equation. y + 6 = –3y + 26
stiks02 [169]

Answer:

Step-by-step explanation:

3y+y = 26-6

4y = 20

4y/4 = 20/4

y = 5

4 0
3 years ago
Read 2 more answers
How do you solve substitution to solve the sytem <br> x+y=2<br> -2x+y=2
lord [1]
So you want to make one of the equations equal to one of the placeholders exg y=x+3

so we have
x+y=2 and
-2x+y=2

I chose to make -2x+y=2 equal to y so
-2x+y=2
add 2x to both sides
y=2+2x

subsitute 2+2x for y in x+y=2
x+2+2x=2
add like terms
3x+2=2
subtract 2 from both sides
3x=0
x=0

subsitute x=0 in x+y=2
0+y=2
y=2

x=0
y=2
5 0
3 years ago
Read 2 more answers
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