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adell [148]
3 years ago
14

One hose can fill a small swimming pool in 95 minutes. A larger hose can fill the pool in 30 minutes. How long will it take the

two hoses to fill the pool working
together?
Mathematics
2 answers:
lianna [129]3 years ago
8 0

Answer:

45 mins for two small hoses and 15 mins for two large ones

Step-by-step explanation:

Lemur [1.5K]3 years ago
3 0

Answer:

I believe this is 65 minutes. if you subtract 30 minutes from 95 you have 65

Step-by-step explanation:

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Find the value z of a standard normal variable Z that satisfies each of the following conditions. In each case, sketch a standar
morpeh [17]

Answer:

a) z = -1.645

b) z = 0.674

Step-by-step explanation:

We have to find the value of z of a standard normal variable Z that satisfies each of the following conditions.

a) 5% of the observations fall below z

=P(Z < z) = 0.05  

Calculation the value from standard normal z table, we have,  

P(Z

b) 25% of the observations fall above z

P(Z > z) = 0.25\\\Rightarrow P(Zz) = 1 - 0.25 = 0.75

Calculation the value from standard normal z table, we have,  

P(Z

3 0
3 years ago
Lashonda wants to buy a new boat but needs money for the down payment. Her parents agree to lend her money at an annual rate of
amm1812

Answer: $6, 720

Step-by-step explanation:

Formular for simple interest =P×R×T

where;

P= 6000

R= 3% = 0.03

T= 4 years

$6000 × 0.03 × 4

= $720

The total amount to be paid back at the end of time will be

$6,000 + $720

=$6, 720

I hope this helps

8 0
3 years ago
What is the sum of the polynomials? (–x2 9) (–3x2 – 11x 4)
STALIN [3.7K]
The sum of the polynomials is -4x^2 -11x-5.
4 0
2 years ago
Pleas help me if you can
Helga [31]
Just use the word bank to fill in the blanks. Each letter they give you in the picture is the beginning of the words. So the first one to the left is a C______ and f_____ that would be Cold front.  Do the same for the others.
6 0
3 years ago
Simplify.<br> Rewrite the expression in the form b^n<br><br> (b^3)^2
Alexxandr [17]

Step-by-step explanation:

a^n={\underbrace{a\cdot a\cdot a\cdot...\cdot a}_{n}

<h2>METHOD 1.</h2>

\left(b^3\right)^2=\underbrace{b^3\cdot b^3}_{2}=\underbrace{b\cdot b\cdot b}_{3}\cdot\underbrace{b\cdot b\cdot b}_{3}=\underbrace{b\cdot b\cdot b\cdot b\cdot b\cdot b}_{6}=b^6

<h2>METHOD 2.</h2>

\left(b^3\right)^2=\underbrace{b^3\cdot b^3}_{2}=b^{3+3}=b^6\qquad\text{used}\ a^n\cdot a^m=a^{n+m}

<h2>METHOD 3.</h2>

\left(b^3\right)^2=\left(\underbrace{b\cdot b\cdot b}_{3}\right)^2=b^2\cdot b^2\cdot b^2=b^{2+2+2}=b^6\\\text{used}\ (ab)^n=a^nb^n,\ a^n\cdot a^m=a^{n+m}

<h2>METHOD 4.</h2>

\left(b^3\right)^2=b^{3\cdot2}=b^6\qquad\text{used}\ \left(a^n\right)^m=a^{nm}

5 0
3 years ago
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