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2 years ago

Angle a is 5/3 of Angle b. Find Angles a and b plz

Mathematics

1 answer:

4vir4ik [10]2 years ago

8 0

Answer:

Angle a = 112.5°

Angle b = 67.5°

Step-by-step explanation:

Angle a + angle b = 180° (Supplementary Angles/angles on a straight line)

Let x = m<b

m<a = ⁵/3(x)

Therefore:

⁵/3x + x = 180

$\frac{5x}{3} + x = 180$

$\frac{5x + 3x}{3} = 180$

$\frac{8x}{3} = 180$

Multiply both sides by 3

$\frac{8x}{3} \times 3 = 180 \times 3$

$8x = 540$

Divide both sides by 8

x = 67.5°

Angle a = ⁵/3(x) = ⁵/3(67.5) = 112.5°

Angle b = x = 67.5°

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The weights of 1250 pumpkins are normally distributed with mean of 28 pounds and a standard deviation of 6 pounds. About how man

Mekhanik [1.2K]

Kropot72
kropot72 3 years ago
This can be solved by using a standard normal distribution table. The z-score for 34 pounds is 1, the reason being that 34 is one standard deviation above the mean of 28 pounds.
Can use the table to find the cumulative probability for z = 1.00 and post the result? If you do this we can do the next simple steps.

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2 years ago

What is the correct answer?

Svetlanka [38]

Answer:

Terms must have the same variable (letter) and the same exponent (little number)

(7x² +3y+ 5) +(9x²+11y- 2)

Opening bracket

7x²+3y+5+9x²+11y-2

keeping like terms together

7x²+9x²+3y+11y+5-2

Since terms having same variable and exponent can be subtracted, added,divided and multiplied

Solving like terms we get

16x²+14y+3 which is a correct answer.

4 0

2 years ago

Which is the greater one 9/10 or 3/4?

Hatshy [7]

9/10,
3/4 = 15/20
9/10 = 18/20
Clearly 9/10 is greater.

4 0

2 years ago

Read 2 more answers

What is the probability that a random person who tests positive for a certain blood disease actually has the disease, if we know

xeze [42]

Answer:

Step-by-step explanation:

Hello!

Any medical test used to detect certain sicknesses have several probabilities associated with their results.

Positive (test is +) ⇒ P(+)

True positive (test is + and the patient is sick) ⇒ P(+ ∩ S)

False-positive (test is + but the patient is healthy) ⇒P(+ ∩ H)

Negative (test is -) ⇒ P(-)

True negative (test is - and the patient is healthy) ⇒ P(- ∩ H)

False-negative (test is - but the patient is sick) ⇒ P(- ∩ S)

The sensibility of the test is defined as the capacity of the test to detect the sickness in sick patients (true positive rate).

⇒ P(+/S) = P(+ ∩ S)

P(S)

The specificity of the test is the capacity of the test to have a negative result when the patients are truly healthy (true negative rate)

⇒ P(-/H) = P(- ∩ H)

P(H)

For this particular blood disease the following probabilities are known:

1% of the population has the disease: P(S)= 0.01

95% of those who are sick, test positive for it: P(+/S)= 0.95 (sensibility of the test)

2% of those who don't have the disease, test positive for it: P(+/H)= 0.02

The probability of a person having the blood sickness given that the test was positive is:

P(S/+)= P(+ ∩ S)

P(+)

The first step you need to calculate the intersection between both events + and S, for that you will use the information about the sickness prevalence in the population and the sensibility of the test:

P(+/S) = P(+ ∩ S)

P(S)

P(+/S)* P(S) = P(+ ∩ S)

P(+ ∩ S) = 0.95*0.01= 0.0095

The second step is to calculate the probability of the test being positive:

P(+)= P(+ ∩ S) + P(+ ∩ H)

Now we know that 1% of the population has the blood sickness, wich means that 99% of the population doesn't have it, symbolically: P(H)= 0.99

Then you can clear the value of P(+ ∩ H):

P(+/H) = P(+ ∩ H)

P(H)

P(+/H)*P(H) = P(+ ∩ H)

P(+ ∩ H) = 0.02*0.99= 0.0198

Next you can calculate P(+):

P(+)= P(+ ∩ S) + P(+ ∩ H)= 0.0095 + 0.0198= 0.0293

Now you can calculate the asked probability:

P(S/+)= P(+ ∩ S) = 0.0095 = 0.32

P(+) 0.0293

I hope it helps!

6 0

2 years ago

Factor the polynomial completely.24x^3-40x^2 45x-75

kumpel [21]

24x^3-40x^2. 45x-75
8x^2(3x-5). 15(3x-5)

(8x^2+15)(3x-5)

3 0

3 years ago