The coordinates of a particle of water "t" seconds after it leaves the end of the fire hose will be
.. (x, y) = (38.4*cos(47.5°)t, -4.9t^2 +38.4*sin(47.5°)t)
Solving for t, we have
.. t = x/(38.4*cos(47.5°)
For x = 25.7 meters, t is about 0.99065 seconds.
Then y will be
.. -4.9*(0.99065)^2 +38.4*sin(47.5°)*0.99065 = 23.238 . . . . meters
The water will hit the building about 23.24 meters above the height of the hose.
Answer:
6m squared
Step-by-step explanation:
cause one of the faces is 2 times 3 and that is 6m squared
First do with the factor out variable m.
m(k+q)=t
Next divide both sides of k+q.
m(k+q)/k+q= t/k+q
Answer is m=t/k+q
The answer is D I think, cause sum means plus and product means times
Answer:
.46%
Step-by-step explanation:
.055/12= .00458= .46%
