A rose garden is formed by joining a rectangle and a semicircle, as shown below. The rectangle is 24 ft long and 16 ft wide.

Mathematics

2 answers:

Margaret [11]3 years ago

6 0

Step-by-step explanation:

Area: L× b

24× 16

384cm²

the area of garden is 384cm²

Alchen [17]3 years ago

4 0

Answer: Using width as diameter=32π Using length as diameter=72π

*I included both possibilities since I didn't see a picture of the way in which the semicircle and rectangle were joined.*

Step-by-step explanation:

In order to solve, you have to know the formula for area of a circle which is A=πr^2 (pi*radius to the 2nd power)

The problem does not give us the radius, but we know that radius is half of the diameter.

To find the diameter, we have to use the side measurement of the rectangle and divide it by 2 to find the radius.

Next, we increase the radius to the 2nd power, giving us the radius of a whole circle.

Finally, we have to divide that by 2 since it's a semi circle otherwise known as half of a circle.

I put the answer in terms of pi since that's the most accurate, but if the question specifically instructs it, you can calculate part of the irrational decimal and round to a certain place value.

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andrey2020 [161]

Answer:

Step-by-step explanation

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Step-by-step explanation:

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2 years ago

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natulia [17]

Answer:

16.7%.

Step-by-step explanation:

There are initially $24 + 15 + 8 = 47$ pencils in the bag.

Take a pencil out of this bag of 47 pencils. 15 out of the 47 pencils blue. Let $A$ represent the event of getting a blue pencil on the first pick. The probability of getting a blue pencil is:

$\displaystyle P(A) = \frac{15}{47}$ .

There are now $47 - 1 = 46$ pencils left in the bag. However, given that the first pencil removed from the bag is blue, the number of red pencils in the bag will still be 24. Take another pencil out of this bag of 46 pencils. Let $B$ represent the event of getting a red pencil on the second pick. The possibility that the second pencil is red given that the first pencil is blue will be: