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Natali5045456 [20]
3 years ago
7

A shipment of sugar fills 14 containers. If each container holds 2 1/4 tons of sugar, what is the amount of sugar in the entire

shipment?
Mathematics
2 answers:
SashulF [63]3 years ago
7 0

You would do 14*2 1/4 so that would be 31.5

liubo4ka [24]3 years ago
4 0

Answer:

31.5

Step-by-step explanation:

First we convert 2 1/4 to an improper  fraction which is 9/4

Then;

We covert 9/4 to decimal form which is 2.25

Then;

We multiply 2.25 with 14(number of containers holding sugar) which is 31.5

Hence the amount of sugar in the entire shipment is 31.5 tons

Hope it helps

Please mark me as Brainlies

:)

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The sum of 5 times a number and 6 is twice that number.
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Trey’s car has a 20-gallon fuel tank. The fuel gauge points to ¼ . If Trey buys 10 gallons of gas, what will be the new reading
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Vinil7 [7]

Answer:

The factors of  2(x+y)^2-9(x+y)-5 is ((x+y)-5)(2x+2y+1)

Step-by-step explanation:

Given polynomial

=>2(x+y)^2-9(x+y)-5

To Find:

The factors of the polynomial =?

Solution:

Lets assume  k = (x+y)

Then 2(x+y)^2-9(x+y)-5 can be written as 2k^2-9k-5

Now by using quadratic formula

k =\frac{-b\pm\sqrt{(b^2-4ac}}{2a}

where

a= 2

b= -9

c= -5

Substituting the values, we get

k =\frac{-b\pm\sqrt{(b^2-4ac)}}{2a}

k =\frac{-(-9) \pm \sqrt{((-9)^2-4(2)(-5)}}{2(2))}

k =\frac{-(-9) \pm \sqrt{(81+40)}}{4}

k =\frac{-(-9) \pm \sqrt{(121)}}{4}

k =\frac{-(-9) \pm 11}}{4}

k= \frac{ 9 \pm 11}{4}

k =  \frac{20}{4}                         k =  \frac{-2}{4}    

k_1 =5                                      k_2 = -\frac{1}{2}

2k^2-9k-5= 2(k-5)(k+\frac{1}{2})

Solving the RHS we get

\frac{2}{2}(k-5)(2k+1)

(k-5)(2k+1)

Substituting k = x+y

((x+y)-5)(2(x+y+1)

((x+y)-5)(2x+2y+1)

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2 years ago
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