Answer:
-8x^2 + 4.
Step-by-step explanation:
Replace the x in f(x) with g(x)
(f o g)(x)
= -8(x^2) + 4.
Answer:
The graph has a domain of all real numbers.
The graph has a y-intercept at
.
The graph has an x-intercept at
.
Step-by-step explanation:
Given: The graph is ![y=\sqrt[3]{x-1}+2](https://tex.z-dn.net/?f=y%3D%5Csqrt%5B3%5D%7Bx-1%7D%2B2)
The domain of a function is a set of input values for which the function is real and defined.
Thus, the graph has a domain of
.
To find the y-intercept: To find the y-intercept, substitute
in
.
![\begin{aligned}y &=\sqrt[3]{x-1}+2 \\&=\sqrt[3]{0-1}+2 \\&=-1+2 \\&=1\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7Dy%20%26%3D%5Csqrt%5B3%5D%7Bx-1%7D%2B2%20%5C%5C%26%3D%5Csqrt%5B3%5D%7B0-1%7D%2B2%20%5C%5C%26%3D-1%2B2%20%5C%5C%26%3D1%5Cend%7Baligned%7D)
Thus, the y-intercept is 
To find the x-intercept: To find the x-intercept, substitute
in
.
![\begin{aligned}y &=\sqrt[3]{x-1}+2 \\0 &=\sqrt[3]{x-1}+2 \\-2 &=\sqrt[3]{x-1} \\(-2)^{3} &=(\sqrt[3]{x-1})^{3} \\-8 &=x-1 \\-7 &=x\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7Dy%20%26%3D%5Csqrt%5B3%5D%7Bx-1%7D%2B2%20%5C%5C0%20%26%3D%5Csqrt%5B3%5D%7Bx-1%7D%2B2%20%5C%5C-2%20%26%3D%5Csqrt%5B3%5D%7Bx-1%7D%20%5C%5C%28-2%29%5E%7B3%7D%20%26%3D%28%5Csqrt%5B3%5D%7Bx-1%7D%29%5E%7B3%7D%20%5C%5C-8%20%26%3Dx-1%20%5C%5C-7%20%26%3Dx%5Cend%7Baligned%7D)
Thus, the x-intercept is 
Answer:
y - 4 = 4 (x + 3)
Step-by-step explanation:
Point-slope form is y - y1 = m (x - x1)
y1 is 4, m is 4, and x1 is -3
When you plug them in, you get: y - 4 = 4 (x + 3)
Note: (x - -3) becomes (x + 3)
I hope this helps!!
Hope you could understand.
If you have any query, feel free to ask.