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3 years ago

Question 2 (1 point)

Mathematics

1 answer:

Vedmedyk [2.9K]3 years ago

7 0

Answer:

Step-by-step explanation:

(-9+2)/2= -7/2= -3.5

(8 + (-1))/2 = 7/2= 3.5

(-3.5, 3.5) is the solution

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A keypad at the entrance of a building has 10 buttons labeled 0 through 9. What is the probability of a person correctly guessin

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A keypad at the entrance of a building has 10 buttons labeled 0 through 9. What is the probability of a person correctly guessing a 9-digit entry code if they know that no digits repeat?

Answer:

the probability of a person correctly guessing a 9-digit entry code if they know that no digits repeat is 0.1

Step-by-step explanation:

We know that probability= number of required outcomes /number of all possible outcome.

From the given information;

the number of required outcome is guessing a 9-digit = 1 outcome

the number of all possible outcome = ¹⁰C₉ since there are 10 numbers and 9 number are to be selected.

Since there are only 9-digit that opens the lock;

the probability of a person correctly guessing a 9-digit entry code is

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3 years ago

Show step by step for equation -8/3x + 4(x + 9/4) = -2/3(x + 12/8) + 3

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3 years ago

How many 9-digit palindromes are there with all the digits being even and each digit appearing no more than twice?

sattari [20]

Answer: 96

Step-by-step explanation:

A palindrome is a number that is the same when reading in both ways (right to left, and left to right), for example, 121

Then, we have 9 digits, and all the digits need to be even.

the options are: 0, 2, 4, 6, 8.

Now, we can tink a 9 digit number as 9 empty slots, and in each slot, we can put a number.

But because this is a palindrome, the first digit must be equal to the ninth, and the second digit must be equal to the eight, and so on.

So we can tink it as actually only 5 slots, where in each slot, we can put an even number, now let's count the options that we have in each selection.

For the first digit we have 4 options: 2, 4, 6 and 8 (0 is not counted here because if the first digit was a 0, then this would not be a 9 digit number).

for the second digit, we have also 4 options (because we already toked one, but now the 0 can be chosen)

for the third digit, we have 3 options

for the fourth digit, we have 2 options

for the fifth digit, we have only one option.

The total number of combinations is equal to the product of the number of options for each selection:

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