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DanielleElmas [232]
2 years ago
15

Question 2 (1 point)

Mathematics
1 answer:
Vedmedyk [2.9K]2 years ago
7 0

Answer:

Step-by-step explanation:

(-9+2)/2= -7/2= -3.5

(8 + (-1))/2 = 7/2= 3.5

(-3.5, 3.5) is the solution

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1,5,9,13 generalize the pattern by finding the nth term
ladessa [460]

Answer:

an= a1 +(n-1)*4

Step-by-step explanation:

a1 = 1, a2 =5, a3 = 9, a4= 13,... an= ?

we see that each term is getting bigger so usually that will happen because of addition or multiplication-in our case add 4 to previous term

a1 = 1,

a2 = a1+(2-1) 4 = 1+4 = 5,

a3 = a1 + (3-1)*4 = a1+8 = 1 + 8 = 9,

a4= a1 + (4-1)*4 = a1 + 12 = 1+12= 13,

...

an= a1 +(n-1)*4

7 0
2 years ago
What is -1 1/4 + 1/2
Marrrta [24]
<h2>-0.75</h2>

plz mark as brainliest

3 0
2 years ago
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What is the GCF of 14 and 21
n200080 [17]
Hey there the answer is, 

<span>The Greates Common Factor (GCF) is:   7
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8 0
3 years ago
Kelly price sells college textbooks on commission. She gets 8 % on the first $7500 of​ sales, 16% on the next $7500 of​ sales, a
Solnce55 [7]

Answer:

The commission would be $ 920.

Step-by-step explanation:

Given,

Sales in 1997 ​= $ 9500,

Since, there is a commision of 8 % on the first $ 7500 of​ sales, 16% on the next $ 7500 of​ sales, and 20% on sales over $ 15,000,

If x represents the total sales,

Commission for x ≤ 7500 = 8% of x = 0.08x,

Commission for 7500 < x ≤ 15000 = 8% of 7500 + 16% of (x-7500)

= 600 + 0.16(x-7500),

Commission for 7500 < x ≤ 15000 = 8% of 7500 + 16% of 7500 + 20% of (x-15000)

= 600 + 1200 + 0.20(x-15000)

= 1800 + 0.20(x-15000)

Thus, the function that shows the given situation,

f(x)=\left\{\begin{matrix}0.08x & x \leq 7500\\ 600+0.16(x-7500) & 7500 < x \leq 15000\\ 1800+0.20(x-15000) & 15000 < x\end{matrix}\right.

Since, 9500 lies between 7500 and 15000,

Therefore, the commission would be,

f(9500)= 600 + 0.16(9500 - 7500) = 600 + 320 = $ 920

7 0
3 years ago
Truth or Dare?<br> Have a nice day/night &lt;3
denpristay [2]

Answer:

Truth plz

Step-by-step explanation:

3 0
2 years ago
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