Question

Can somebody please help with these two questions?

Answer 1

Answer:

#3: x is approximately 0.37, -5.37, #4: x is approximately 4.19, -1.19

Step-by-step explanation:

You can solve using the quadratic equation or by solving with the perfect square

$\frac{-b+/-\sqrt{b^{2}-4ac} }{2a}$ = $x^{2}+5x-2=0\\ \frac{-5+/-\sqrt{5^{2}-4(1)(-2) }}{2(1)}$

x is approximately 0.37, -5.37