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lisabon 2012 [21]
3 years ago
12

Hi, can someone help me on this as quick as possible, ty!

Mathematics
1 answer:
kolbaska11 [484]3 years ago
4 0

Answer:

3 is A

do you need four?

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The steps to solve it. Unsure what step I am missing.<br><br>solve: e^(6x)=6e^(x)
Inessa [10]
<em>Solve: </em>e^{6x} = 6e^{x}

Taking the natural log of both sides will cancel out the left hand side, since exponentials and logarithmic functions are inverses of each other.

ln(e^{6x}) = ln(6e^{x})

Using the property, log(ab) = log(a) + log(b), we can simplify the right hand side, and the left side simply will cancel down to 6x.

6x = ln(6) + ln(e^{x})
6x = ln(6) + x

Isolate the variable to solve directly for x.
6x - x = ln(6)
5x = ln(6)

\therefore x = \frac{ln(6)}{5}
7 0
4 years ago
How can you tell the difference between a strong linear association and a weak linear association?
maw [93]
I think it’s A for some reason
6 0
3 years ago
What is the ratio between 6 and 4?
Firdavs [7]

Answer:

3:2

Step-by-step explanation:

You have to divide both sides by the <u>same </u>number

7 0
4 years ago
Read 2 more answers
AA, B BB, and C CC are collinear, and B BB is between A AA and C CC. The ratio of A B ABA, B to B C BCB, C is 3 : 1 3:13, colon,
Katena32 [7]

Answer:

  C = (1, -1)

Step-by-step explanation:

For that 3:1 division, the calculated value of point B is ...

  B = (3C +1A)/(3+1)

Solving for the value of C, we find ...

  4B = 3C + A . . . . multiply by 4

  4B -A = 3C . . . . . subtract A; next divide by 3.

  C = (4B -A)/3 = ((4(-1)-(-7))/3, (4(0)+-3)/3) . . . . substitute given values

  C = (3/3, -3/3) . . . . simplify a bit

  C = (1, -1)

7 0
3 years ago
A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 402 gram setting. It is
lidiya [134]

Answer:

The value of t test statistics is -2.25.

Step-by-step explanation:

We are given that a manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 402 gram setting. It is believed that the machine is under filling the bags.

A 25 bag sample had a mean of 393 grams with a standard deviation of 20.

<u><em>Let </em></u>\mu<u><em> = mean filling of bags by the machine.</em></u>

So, Null Hypothesis, H_0 : \mu \geq 402 gram     {means that the the machine is not under filling the bags}

Alternate Hypothesis, H_A : \mu < 402 gram     {means that the the machine is under filling the bags}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                       T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean bag filling = 393 grams

            s = sample standard deviation = 20 grams

            n = sample of bags = 25

So, <u><em>test statistics</em></u>  =  \frac{393-402}{\frac{20}{\sqrt{25} } }  ~ t_2_4

                               =  -2.25

The value of t test statistics is -2.25.

5 0
3 years ago
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