Answer:
![\dfrac{11}{20}](https://tex.z-dn.net/?f=%5Cdfrac%7B11%7D%7B20%7D%3C%5Cdfrac%7B5%7D%7B9%7D)
A is correct.
Step-by-step explanation:
Given: ![\dfrac{11}{20}\text{ and }\dfrac{5}{9}](https://tex.z-dn.net/?f=%5Cdfrac%7B11%7D%7B20%7D%5Ctext%7B%20and%20%7D%5Cdfrac%7B5%7D%7B9%7D)
We need to compare the two fraction.
We can compare either greater , less or equal.
If we compare two fraction. First we make their denominator same.
Denominators are 20 and 9
We will find the LCD of 20 and 9
20 = 2 x 2 x 5
9 = 3 x 3
LCD = 2 x 2 x 3 x 3 x 5 = 180
![\text{First Fraction}\rightarrow \dfrac{11\times 9}{20\times 9}\Rightarrow \dfrac{99}{180}](https://tex.z-dn.net/?f=%5Ctext%7BFirst%20Fraction%7D%5Crightarrow%20%5Cdfrac%7B11%5Ctimes%209%7D%7B20%5Ctimes%209%7D%5CRightarrow%20%5Cdfrac%7B99%7D%7B180%7D)
![\text{Second Fraction}\rightarrow \dfrac{5\times 20}{9\times 20}\Rightarrow \dfrac{100}{180}](https://tex.z-dn.net/?f=%5Ctext%7BSecond%20Fraction%7D%5Crightarrow%20%5Cdfrac%7B5%5Ctimes%2020%7D%7B9%5Ctimes%2020%7D%5CRightarrow%20%5Cdfrac%7B100%7D%7B180%7D)
Now, we can see their denominator are same.
We will compare the numerator.
99<100
Thus,
![\dfrac{99}{180}](https://tex.z-dn.net/?f=%5Cdfrac%7B99%7D%7B180%7D%3C%5Cdfrac%7B100%7D%7B180%7D)
![\dfrac{11}{20}](https://tex.z-dn.net/?f=%5Cdfrac%7B11%7D%7B20%7D%3C%5Cdfrac%7B5%7D%7B9%7D)
Hence,
correct.